Question

-A pool ball leaves a 0.70 meter high table with an initial velocity of 2.4 m/s. Predict the time required for the pool ball to fall to the ground.
-A rock is thrown with a velocity of 23.7 m/s horizontally off the top of a bridge and lands in the water 35.0 meters away. What is the vertical velocity just before the rock hits the water below?


-A plane moving at a velocity of 205 m/s drops a piece of cargo which lands 6.5 seconds later. How far did the cargo box land after it's release?

Answer 1

Answer:

First Question:

If the initial velocity is horizontal: It doesn't really matter how fast it is going horizontally if we want to calculate time.

Since it rolled off the table, the initial vertical velocity is 0. The displacement will be -0.7 meters since the table is 0.7 meters high. The acceleration will be -9.8 m/s^2 because that's just earth's gravity.

We can plug the variables into the formula Displacement = Initial Velocity*Time + 1/2*Acceleration*Time^2:

$-0.7 = 0\cdot t + 1/2\cdot-9.8\cdot t^2\\-0.7 = -4.9*t^2\\t^2 = \frac{10}{7} \\t = \sqrt{\frac{10}{7}}$

Rounded to the nearest hundredths, the answer is 1.2 seconds.

Second Question:

We can use the horizontal variables to find out the time to solve for the vertical velocity.

The acceleration is going to be 0(assuming no air resistance), the initial velocity is going to be 23.7 m/s, and the displacement is going to be 35.0 meters.

Again, we can plug the variables into the formula Displacement = Initial Velocity*Time + 1/2*Acceleration*Time^2:

$35 = 23.7\cdot t + 1/2\cdot 0\cdot t^2\\35 = 23.7\cdot t\\t = \frac{35}{23.7}$

Rounded to the nearest hundredth, t = 1.48.

Now, we're going to find the vertical variables:

The acceleration will be -9.8 m/s^2 because that's just earth's gravity. The initial velocity will be 0 because the rock was launched horizontally. The time, as calculated before, is 1.48.

Now, we can plug t into the formula Velocity = Initial Velocity + Acceleration *Time:

$v = 0 + -9.8\cdot1.48\\v = -14.504$

Rounded to the nearest hundredth, the answer is -14.5 meters per second.

Third Question:

Let's find the horizontal variables:

Assuming no air resistance, the final velocity is 205 m/s. The initial velocity will also be 205 m/s. The time will be 6.5 seconds.

We can use the formula Displacement = (Final Velocity+Initial Velocity)/2 * Time. In this case, the final velocity and the initial velocity are the same, so the formula reduces to Displacement = Final Velocity * Time:

$d = 205\cdot6.5\\d = 1332.5$

Therefore, the answer is 1332 meters.

I really hoped this helped you because I spent more than 1 hour explaining. If you have more questions don't hesitate to ask. If it helped you, please consider giving me brainliest? :)

Answer 2

Answer:

0.70+2.4=23.7+35.0=answer

Explanation: