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nata0808 [166]
4 years ago
15

A used car already has 40,000 miles on its odometer. The average owner will drive 12,000 miles per year. Which function best mod

els the linear relationship? y = 12,000x + 40,000 y = 40,000x + 12,000 y = 52,000x + 12,000 y = 12,000x - 40,000
Physics
1 answer:
bekas [8.4K]4 years ago
5 0

Answer:

y = 12,000x + 40,000

Explanation:

A linear relationship that would model the mileage of the car in this example is:

y=mx+q

where

y is the number of miles

x is the number of years

m is the number of miles driven per year

q is the number of miles already in the car at x=0

In this problem, we have

m = 12,000 (number of miles driven per year)

q = 40,000 (number of miles already in the car at x=0)

So substituting into the equation we get

y=12,000 x + 40,000

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In a city park a nonuniform wooden beam 5.00 m long is suspended horizontally by a light steel cable at each end. The cable at t
DanielleElmas [232]

Answer:

Explanation:

System of forces in balance

ΣFx = 0

ΣFy = 0

∑MA = 0

MA = F*d

Where:

∑MA  : Algebraic sum of moments in the the point (A)

MA : moment in the point A ( N*m)

F  : Force ( N)

d  : Horizontal distance of the force to the point A ( N*m

Forces acting on the beam

T₁ = 620 N : Tension in cable 1 ,at angle of 30° with the vertical on the left

T₂ : Tension in cable 2, at angle of 50.0° with the vertical on the right.

W : Weight of the beam

x-y T₁ and T₂ components

T₁x= 620*sin30° = 310 N

T₁y= 620*cos30° = 536.94 N

T₂x= T₂*sin50°

T₂y= T₂*cos50°

Calculation of the T₂

ΣFx = 0  

T₂x-T₁x = 0

T₂x=T₁x

T₂*sin50° =  310 N

T₂ =  310 N /sin50°

T₂ = 404.67 N

Calculation of the W

ΣFy = 0  

T₂y+T₁y-W = 0

(404.67) *cos50° +  536.94 = W

W= 260.12+ 536.94

W= 797.06 N

Location of the center of gravity of the beam

∑MA = 0 , point (A) (point where the  cable 2  of the right is located on the beam)

T₁y(5)-W(d) = 0

T₁y(5) = W(d)

d = T₁y(5)/W

d =  536.94(5) / 797.06

d = 3.37m

The center of gravity is located at 3.37m measured from the right end of the beam

5 0
3 years ago
Jules verne wrote a book called twenty thousand leagues under the sea. is the ocean really that deep?explain.
svetoff [14.1K]

no... probably not, jules verne is most likely using HYPERBOLE to prove a point that the ocean is VERY deep.

7 0
4 years ago
After 60 days, 100g of a certain element has decayed to only 12.5g.
vagabundo [1.1K]

Answer:

8 days

Explanation:

3 0
3 years ago
An interference pattern is produced by light with a wavelength 520 nm from a distant source incident on two identical parallel s
Goshia [24]

Answer:

1) θ = 0.00118 rad, 2)  θ = 0.00236 rad , 3) I / I₀ = 0.1738, 4)  I / Io = 0.216

Explanation:

In the double-slit interference phenomenon it is explained for constructive interference by the equation

          d sin θ = m λ

1) the first order maximum occurs for m = 1

           sin θ = λ  / d

           θ = sin⁻¹ λ  / d

let's reduce the magnitudes to the SI system

           λ  = 520 nm = 520 10⁻⁹  θ = 0.00118 radm

           d = 0.440 mm = 0.440 10⁻³ m ³

let's calculate

           θ = sin⁻¹ (520 10⁻⁹ / 0.44 10⁻³)

            θ = sin⁻¹ (1.18 10⁻³)

            θ = 0.00118 rad

2) the second order maximum occurs for m = 2

            θ = sin⁻¹ (m λ  / d)

            θ = sin⁻¹ (2 5¹20 10⁻⁹ / 0.44 10⁻³)

            θ = 0.00236 rad

3) To calculate the intensity of the interference spectrum, the diffraction phenomenon must be included, so the equation remains

          I = I₀ cos² (π d sin θ /λ ) sinc² (pi b sin θ /λ )

where the function sinc = sin x / x

and b is the width of the slits

we caption the values

             x = π 0.310 10⁻³ sin 0.00118 / 520 10⁻⁹)

             x = 2.21

            I / I₀ = cos² (π 0.44 10⁻³ sin 0.00118 / 520 10⁻⁹) (sin (2.21) /2.21)²

remember angles are in radians

            I / I₀ = cos² (3.0945) [0.363] 2

            I / I₀ = 0.9978 0.1318

            I / I₀ = 0.1738

4) the maximum second intensity is

            I / I₀ = cos² (π d sinθ / λ) sinc² (πb sin θ /λ)

            x =π 0.310 10⁻³ sin 0.00236 / 520 10⁻⁹)

            x = 4.41

            I / Io = cos² (π 0.44 10⁻³ sin 0.00236 / 520 10⁻⁹) (sin 4.41 / 4.41)²

            I / Io = cos² 6.273    0.216

            I / Io = 0.216

.

7 0
3 years ago
What is the mass of an object that has a weight of 52N? (n=newtons)<br><br>Answer is in kilograms
polet [3.4K]
Hi there!

The answer you are looking for.....



<span>5.3025kg!</span>





Hope this helps you!

Have a great day!

8 0
4 years ago
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