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nata0808 [166]
4 years ago
15

A used car already has 40,000 miles on its odometer. The average owner will drive 12,000 miles per year. Which function best mod

els the linear relationship? y = 12,000x + 40,000 y = 40,000x + 12,000 y = 52,000x + 12,000 y = 12,000x - 40,000
Physics
1 answer:
bekas [8.4K]4 years ago
5 0

Answer:

y = 12,000x + 40,000

Explanation:

A linear relationship that would model the mileage of the car in this example is:

y=mx+q

where

y is the number of miles

x is the number of years

m is the number of miles driven per year

q is the number of miles already in the car at x=0

In this problem, we have

m = 12,000 (number of miles driven per year)

q = 40,000 (number of miles already in the car at x=0)

So substituting into the equation we get

y=12,000 x + 40,000

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The instantaneous speed of a particle moving along one straight line is v(t) = ate−6t, where the speed v is measured in meters p
beks73 [17]

Answer:

v_max = (1/6)e^-1 a

Explanation:

You have the following equation for the instantaneous speed of a particle:

v(t)=ate^{-6t}   (1)

To find the expression for the maximum speed in terms of the acceleration "a", you first derivative v(t) respect to time t:

\frac{dv(t)}{dt}=\frac{d}{dt}[ate^{-6t}]=a[(1)e^{-6t}+t(e^{-6t}(-6))]  (2)

where you have use the derivative of a product.

Next, you equal the expression (2) to zero in order to calculate t:

a[(1)e^{-6t}-6te^{-6t}]=0\\\\1-6t=0\\\\t=\frac{1}{6}

For t = 1/6 you obtain the maximum speed.

Then, you replace that value of t in the expression (1):

v_{max}=a(\frac{1}{6})e^{-6(\frac{1}{6})}=\frac{e^{-1}}{6}a

hence, the maximum speed is v_max = ((1/6)e^-1)a

5 0
3 years ago
Use Coulomb’s law to derive the dimension for the permittivity of free space. <br><br><br><br>​
MrRa [10]

Answer:

Coulomb's law is:

F = \frac{1}{4*pi*e0} *(q1*q2)/r^2

First, force has units of Newtons, the charges have units of Coulombs, and r, the distance, has units of meters, then, working only with the units we have:

N = (1/{e0})*C^2/m^2

then we have:

{e0} = C^2/(m^2*N)

And we know that N = kg*m/s^2

then the dimensions of e0 are:

{e0} = C^2*s^2/(m^3)

(current square per time square over cubed distance)

And knowing that a Faraday is:

F = C^2*S^2/m^2

The units of e0 are:

{e0} = F/m.

7 0
3 years ago
What is the weight of a box with a mass of 150 kg on Earth?
joja [24]

The weight of the box with the given mass on Earth is 1470 Newtons.

Given the data in the question;

  • Mass of box; m = 150kg
  • Weight of box; W = \ ?

<h3>Weight</h3>

Weight is the force acting on the mass of a particular object or particle due to gravity. It is the gravitational force acting on an object with mass. It is measured in newtons. It is expressed as;

W = m * g

Where m is mass of object and g is acceleration due to gravity on earth ( g = 9.8m/s^2 )

To find the weight of the box, we substitute our values into the expression above;

W = 150kg * 9.8m/s^2\\\\W = 1470kgm/s^2\\\\W = 1470N

Therefore, the weight of the box with the given mass on Earth is 1470 Newtons.


Learn more about weight: brainly.com/question/19540959

3 0
3 years ago
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The type of exercise that you choose will determine what _____will be worked
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Does muscle go in the blank?
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3 years ago
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Is a reflection matter?
azamat

Answer:

Yes, because everything bounce off in every surface around any object.

Explanation:

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3 years ago
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