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OLga [1]
3 years ago
9

NEED HELP ASAP!!

Chemistry
1 answer:
den301095 [7]3 years ago
5 0

Answer:

3rd option

Explanation:

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What creates a thermocline?
vredina [299]

Answer:

here are the answers to all the questions on the quiz Phytoplankton

There would be no ocean life without _____.

thermocline

marine snow  

phytoplankton

runoff

Phytoplankton is the answer.

What creates a thermocline?

a series of strong ocean storms  

a difference in water temperature

a difference in the amount of phytoplankton

a change in the phytoplankton population

a difference in water temperature is the answer

What limits the growth of phytoplankton?

It is limited by the amount of water that runs off into the ocean.

It is limited by the number of fish eating the phytoplankton directly.

It is limited by the depth of the water in the ocean.  

It is limited by the amount of nutrients in the water.

It is limited by the amount of nutrients in the water is the answer

 

What are phytoplankton? (Select all that apply.)  

They are organisms that support all other life in the oceans.

They are tiny plants that drift with the currents of the ocean.

They are small plants and animals that exist both on land and in the ocean.

They are microscopic animals that drift with the currents of the wind.

They are organisms that support all other life in the oceans.

They are tiny plants that drift with the currents of the ocean.

are the answers

Which is a possible food chain in the ocean from start to finish?  

phytoplankton, zooplankton, small fish, large fish, large shark

zooplankton, phytoplankton, large fish, small fish, large shark

phytoplankton, large shark, zooplankton, large fish, small fish

large shark, large fish, small fish, zooplankton, phytoplankton

phytoplankton, zooplankton, small fish, large fish, large shark is the answer

Hope this helps!

did the quiz and got 100%

May I get braineist pls

6 0
2 years ago
Write the chemical formula for
nataly862011 [7]
Ba2Cl
NaS2
The numbers are in subscript
6 0
3 years ago
Read 2 more answers
PLEASE HELP <3
frutty [35]
In order for carbon to be stable and have 8 electrons, it must make 4 total covalent bonds.

In prefer for oxygen to be stable and have 8 electrons, it must make 2 covalent bonds.

So, we can deduce that CO2 looks like this:

O=C=O

This molecule has two double bonds.

Pssst...Can I get a brainliest?
8 0
3 years ago
BRANILEST IF RIGHT <br><br> WAVE A OR B
Serhud [2]
I think it’s A but I’m not sure.
3 0
3 years ago
Read 2 more answers
Dinitrogen tetraoxide, N2O4, decomposes to nitrogen dioxide, NO2, in a first-order process. If k = 1.5 x 103 s-1 at 5 ºC and k =
Arada [10]

Answer:

The activation energy for the decomposition = 33813.28 J/mol

Explanation:

Using the expression,

\ln \dfrac{k_{1}}{k_{2}} =-\dfrac{E_{a}}{R} \left (\dfrac{1}{T_1}-\dfrac{1}{T_2} \right )

Wherem  

k_1\ is\ the\ rate\ constant\ at\ T_1

k_2\ is\ the\ rate\ constant\ at\ T_2

E_a is the activation energy

R is Gas constant having value = 8.314 J / K mol  

Thus, given that, E_a = ?

k_2=4.0\times 10^3s^{-1}

k_1=1.5\times 10^3s^{-1}  

T_1=5\ ^0C  

T_2=25\ ^0C  

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (5 + 273.15) K = 278.15 K  

T = (25 + 273.15) K = 298.15 K  

T_1=278.15\ K

T_2=298.15\ K

So,

\ln \frac{1.5\times 10^3}{4.0\times 10^3}\:=-\frac{E_{a}}{8.314}\times \left(\frac{1}{278.15}-\frac{1}{298.15}\right)

E_a=-\ln \frac{1.5\times \:10^3}{4.0\times \:10^3}\:\times \frac{8.314}{\left(\frac{1}{278.15}-\frac{1}{298.15}\right)}

E_a=-\frac{8.314\ln \left(\frac{1.5\times \:10^3}{4\times \:10^3}\right)}{\frac{1}{278.15}-\frac{1}{298.15}}

E_a=-\frac{689483.53266 \ln \left(\frac{1.5}{4}\right)}{20}

E_a=33813.28\ J/mol

<u>The activation energy for the decomposition = 33813.28 J/mol</u>

8 0
3 years ago
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