Compute the ball's angular speed <em>v</em> :
<em>v</em> = (1 rev) / (2.3 s) • (2<em>π</em> • 180 cm/rev) • (1/100 m/cm) ≈ 4.917 m/s
Use this to find the magnitude of the radial acceleration <em>a</em> :
<em>a</em> = <em>v </em>²/<em>R</em>
where <em>R</em> is the radius of the circular path. We get
<em>a</em> = <em>v</em> ² / (180 cm) = <em>v</em> ² / (1.8 m) ≈ 13.43 m/s²
The only force acting on the ball in the plane parallel to the circular path is the tension force. By Newton's second law, the net force acting on the ball has magnitude
∑ <em>F</em> = <em>m</em> <em>a</em>
where <em>m</em> is the mass of the ball. So, if <em>t</em> denotes the magnitude of the tension force, then
<em>t</em> = (1.6 kg) (13.43 m/s²) ≈ 21 N
Answer:
The amplitude of the wing tip's motion is 1.6 mm.
Explanation:
Given that,
Beat = 250 /s
Speed = 2.5 m/s
We need to calculate the amplitude of the wing tip's motion
Using the equation for the maximum velocity
Where,
v = speed
f = frequency
A = amplitude
Put the value into the formula
Hence, The amplitude of the wing tip's motion is 1.6 mm.
Directly proportional to volume, according to charles’s law
Answer:
Stellar Spectra Classification The patterns of lines detected in stellar spectra are used by astronomers to classify stars into spectral classes. These spectral classes are a measure of a star's surface temperature since the temperature of a star dictates which absorption lines are present in its spectrum.
Explanation:
Answer:
A
Explanation:
it's hard to explain... sorry
