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harina [27]
3 years ago
8

The world's fastest humans can reach speeds of about 11 m/s.In order to increase his gravitational potential energy by an amount

equal to his kinetic energy at full speed, how high would such a sprinter need to climb?
Physics
1 answer:
xeze [42]3 years ago
5 0

Answer:

The sprinter need to climb 6.17 m

Explanation:

From the question,

Ep = Ek...................... Equation 1

Where Ep = potential energy, Ek = kinetic energy.

therefore,

mgh = 1/2mv².................... Equation 2

Where m = mass of the human, v = speed, h = height, g = acceleration due to gravity.

making h the subject of formula in equation 2

h = 1/2v²/g...................... Equation 3

Given: v = 11 m/s

Constant: g = 9.8 m/s²

Substituting these values into equation 3,

h = 1/2(11²)/9.8

h = 6.17 m.

Therefore the sprinter need to climb 6.17 m

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Say I have a series circuit with 20v and four 65 ohm resistors, what is the current in each resistor?
Komok [63]
Data:

E = 20 V
R_{1} = 65\Omega
R_{2} = 65\Omega
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<span>Now that we have all the values ​​we need properly identified, simply calculate the equivalent total resistance of the circuit and the intensity of the total electric current using the Ohm's Law:

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<span>Like this:
</span>
I_{T} =  \frac{E}{ R_{T} }

I_{T} = \frac{20}{ 260 }
I_{T} = 0,076923076...

\boxed{\boxed{I_{T} \approx 0,07A}} 
Answer:
<span>The intensity of the total electric current 
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P.S:. Since the association is in series, the current of 0.07A is the same for all resistors.
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