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stealth61 [152]
2 years ago
13

What is the main difference between analog anddigital technology?a. Digital technology reproduces sound more faithfullythan anal

og technology.b. Analog technology stores information as soundwaves; digital technology stores it as strings of onesand zeroes.c. Analog technology can be used to record sound andimages; digital technology can only be used to recordsound.d. Analog technology is based on binary code; digitaltechnology is based on electromagnets
Physics
1 answer:
daser333 [38]2 years ago
3 0

Answer:

Answer b)

Explanation:

The correct answer is that analog technology stores information as sound-waves, while digital technology stores it as strings of ones and zeroes. So pick answer b)

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Answer:

The magnitude of electron acceleration is 2.34 \times 10^{15} \frac{m}{s^{2} }

Explanation:

Given:

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Speed of electron v = 35.5 \%c

Current I = 17.7 A

For finding the acceleration,

First find the magnetic field due to wire,

  B = \frac{\mu _{o}I }{2\pi r }

Where \mu_{o} = 4\pi   \times 10^{-7}

  B = \frac{4\pi \times 10^{-7}  \times 17.7 }{2\pi (2.83 \times 10^{-2} ) }

  B = 12.50 \times 10^{-5} T

The magnetic force exerted on the electron passing through straight wire,

  F = qvB  

  F = 1.6 \times 10^{-19} \times 0.355 \times 3 \times 10^{8} \times 12.50 \times 10^{-5}

  F = 21.3 \times 10^{-16} N

From the newton's second law

  F = ma

Where m = mass of electron = 9.1 \times 10^{-31} kg

So acceleration is given by,

   a = \frac{F}{m}

   a = \frac{21.3 \times 10^{-16} }{9.1 \times 10^{-31} }

   a = 2.34 \times 10^{15} \frac{m}{s^{2} }

Therefore, the magnitude of electron acceleration is 2.34 \times 10^{15} \frac{m}{s^{2} }

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Answer:

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