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stealth61 [152]
3 years ago
13

What is the main difference between analog anddigital technology?a. Digital technology reproduces sound more faithfullythan anal

og technology.b. Analog technology stores information as soundwaves; digital technology stores it as strings of onesand zeroes.c. Analog technology can be used to record sound andimages; digital technology can only be used to recordsound.d. Analog technology is based on binary code; digitaltechnology is based on electromagnets
Physics
1 answer:
daser333 [38]3 years ago
3 0

Answer:

Answer b)

Explanation:

The correct answer is that analog technology stores information as sound-waves, while digital technology stores it as strings of ones and zeroes. So pick answer b)

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Find the specific heat of a substance that requires 8000 J of energy to heat up 400g by 20 C?
monitta

Answer:

c=1\ J/g^\circ C

Explanation:

Given that,

Heat required, Q = 8000 J

Mass, m = 400 g

The change in temperature, \Delta T = 20^{\circ}

The heat required due to change in temperature is given by :

Q=mc\Delta T\\\\c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{8000 }{400\times 20}\\\\c=1\ J/g^\circ C

So, the specific heat of the substance is 1\ J/g^\circ C

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3 years ago
I need help with this one <br><br> Coulombs law <br><br> 100 points and brainliest
Ganezh [65]

Answer:

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3 years ago
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Let's begin by determining the equilibrium position of a seesaw pivot. You and a friend play on a seesaw.Your mass is____
expeople1 [14]

Answer:

1.2 m from the left end

Explanation:

M = mass of the person = 90 kg

m  = mass of friend = 60 kg

r  = distance of pivot from the person or from the left end

L  = length of the seesaw board = 3.0 m

s  = distance of pivot from the friend or from right end = L - r = 3 - r

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3 years ago
Hiran is standing beside the road when he hears a bird flying away from hip and chirping. The bird’s chirp has a frequency of 18
Murrr4er [49]

The frequency of bird chirping hear by hiran will be 1.77 kHz.

<u>Explanation:</u>

As per Doppler effect, the observer will feel a decrease in the frequency of the receiving signal if the source is moving away from the observer. So the shifted frequency is obtained using the below equation:

f'=\frac{c}{c+v_{s} }f

Here , c is the speed of sound, Vs is the velocity of source with which it is moving away. f is the original frequency of source and f' is the frequency shift heard by the observer.

As here, f = 1800 Hz, Vs= 6 m/s and c = 343 m/s, then

f'=\frac{343}{343+6} \times 1800=1.77\ kHz

So, the frequency of bird chirping hear by hiran will be 1.77 kHz.

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3 years ago
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