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Xelga [282]
3 years ago
7

A force of 20 N acts on a rocket for 350 s, causing the rocket's velocity to increase. Calculate the impulse of the force and by

how much does the rocket's momentum increase?
Physics
1 answer:
Alex73 [517]3 years ago
7 0
<span>The formula for impulse is force times time, so impulse would be 20N x 350s = 7000 N x s. Since this impulse of 7000 N x s, the momentum would also be the same since the velocity increased after this impulse.</span>
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A uniform electric field of magnitude 6.8 × 10 5 N/C points in the positive x direction. (a) Find the electric potential differe
Naya [18.7K]

Answer:

i)4080000V

ii)4080000V

iii)5766400v

Explanation:

Hello!

To solve this problem we will use the following steps

1. We will use the equation that defines the distance between two points in order to find the distance from the origin to each of the points that the problem asks for.

d=\sqrt{x^2+y^2}

x= horizonalt component

y=vertical component

d=distance

i)

x=0

y=6

d=\sqrt{0^2+6^2}=6m

ii)

x=6

y=0

d=\sqrt{6^2+0^2}=6m

iii).

x=6

y=6

d=\sqrt{6^2+6^2}=8.48m

2.we calculate the voltage at each point using the equation that relates the distance the voltage and the electric field

V=Ed

where

V=EPD= the electric potential difference

E=electric field  magnitude=6.8 × 10^5 N/C.

d=distance

i)

V=Ed=(6.8 × 105 N/C.)(6)=4080000V

ii)

i)

V=Ed=(6.8 × 105 N/C.)(6)=4080000V

iii)

i)

V=Ed=(6.8 × 105 N/C.)(8.48m)=5766400v

8 0
3 years ago
A. Two point charges totaling 7.50 µC exert a repulsive force of 0.100 N on one another when separated by 0.911 m. What is the c
andriy [413]

coulomb's law

f repulsive = q1q2/4 pi epsilon nought r squared

0.1= q1q2/4 pi epsilon nought 0.911 squared

q1+q2= 7.50 µC

0.1= q1(7.5µC-q1)/4 pi epsilon nought 0.911 squared

solve for q1

7 0
3 years ago
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