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Xelga [282]
2 years ago
7

A force of 20 N acts on a rocket for 350 s, causing the rocket's velocity to increase. Calculate the impulse of the force and by

how much does the rocket's momentum increase?
Physics
1 answer:
Alex73 [517]2 years ago
7 0
<span>The formula for impulse is force times time, so impulse would be 20N x 350s = 7000 N x s. Since this impulse of 7000 N x s, the momentum would also be the same since the velocity increased after this impulse.</span>
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a spherical mirror is cut in half horizontally will an image be formed by the bottom half of the mirror how
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7 0
3 years ago
1.)Two objects, one of m=20,000 kg, and another of 12,500 kg, are placed at a distance of 5 meters apart. What is the force of g
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1) 6.67\cdot 10^{-4} N

The force of gravitation between the two objects is given by:

F=G\frac{m_1 m_2}{r^2}

where

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m1 = 20,000 kg is the mass of the first object

m2 = 12,500 kg is the mass of the second object

r = 5 m is the distance between the two objects

Substituting the numbers inside the equation, we find

F=(6.67\cdot 10^{-11})\frac{(20,000 kg)(12,500 kg)}{(5 m)^2}=6.67\cdot 10^{-4} N


2)  2.7\cdot 10^{-3} N

From the formula in exercise 1), we see that the force is inversely proportional to the square of the distance:

F \sim \frac{1}{r^2}

this means that if we cut in a half the distance without changing the masses, the magnitude of the forces changes by a factor

F'\sim \frac{1}{(r/2)^2}=4 \frac{1}{r^2}=4F

So, the gravitational force increases by a factor 4. Therefore, the new force will be

F' = 4 F=4(6.67\cdot 10^{-4} N)=2.7\cdot 10^{-3} N


3)  12.5 Nm

The torque is equal to the product between the magnitude of the perpendicular force and the distance between the point of application of the force and the centre of rotation:

\tau=Fd

Where, in this case:

F = 25 N is the perpendicular force

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By using the equation, we find

\tau=(25 N)(0.5 m)=12.5 Nm


4) 0.049 kg m^2/s

The relationship between angular momentum (L), moment of inertia (I) and angular velocity (\omega) is:

L=I\omega

In this problem, we have

I=0.007875 kgm^2

\omega=6.28 rad/s

So, the angular momentum is

L=I\omega=(0.007875 kgm^2)(6.28 rad/s)=0.049 kg m^2/s

6 0
2 years ago
Which is true regarding the penetrating power of radiation? (2 points) Select one:
Monica [59]

Answer:d

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3 0
3 years ago
According to Newton's first law of motion, what is required to make an object slow down? Enter your answer in the space provided
LenaWriter [7]

<u>Answer:</u>

According to newton's first law of motion, friction is required to make an object slow down.

<u>Explanation:</u>

According to the Newton's first law of motion, for an object to change its velocity (either a change in the magnitude or the direction), there must be a cause to it which is defined as a net external force.

For example, an object which is sliding across a table or floor slows down due to the net force of friction that is acting on that object.

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