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AleksandrR [38]
1 year ago
12

Two cars, with the same mass and traveling at the same speed, hit large trees head-on. One car has a rigid body that undergoes l

ittle or no deformation in the collision. The other has ``crumple zones'': portions of the body designed to crumple and deform in such a collision. How does this improve the chances that the driver of the second car will survive the event
Physics
1 answer:
nordsb [41]1 year ago
8 0

The crumple zones in the second car will improve the chance of survival of the driver because it will act as shock absorber, reducing the impact of the force on the driver.

<h3>Newton's third law of motion</h3>

According to Newton's third law of motion, action and reaction are equal and opposite.

The car with rigid body will exert maximum force to the driver while the car with crumple zone will exert lesser force to the driver since the crumple zone will act as shock absorber, reducing the impact of the force on the driver.

Thus, the crumple zones in the second car will improve the chance of survival of the driver because it will act as shock absorber, reducing the impact of the force on the driver.

Learn more about Newton's third law of motion here: brainly.com/question/25998091

#SPJ1

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The equation we use is mλ=dsinθ for intensity maximas. We are given at the first maximum (m=1), it occurs at 17.8 degrees. Thus we can solve for d by substituting known values into our equation.

(1) (632.8*10^-9m)=dsin(17.8) => d = 2.07*10^-6m

Next we want to find the angle at the second maximum (m=2) so we need to solve for θ.

(2) (632.8*10^-9m) = (2.07*10^-6m)sinθ

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Hopes this helps!

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3Q / 4 pi (R^3 - r^3)

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Suppose that in a lightning flash the potential difference between a cloud and the ground is 0.96×109 V and the quantity of char
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(a) 2.98\cdot 10^{10} J

The change in energy of the transferred charge is given by:

\Delta U = q \Delta V

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q is the charge transferred

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Here we have

q=31 C

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If the energy released is used to accelerate the car from rest, than its final kinetic energy would be

K=\frac{1}{2}mv^2

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Here the energy given to the car is

K=2.98\cdot 10^{10} J

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