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Pepsi [2]
3 years ago
12

There are 4 jacks and 13 clubs in a standard, 52-card deck of playing cards. What is the probability that a card picked at rando

m from a standard deck of playing cards is a club or a jack?
Mathematics
1 answer:
ale4655 [162]3 years ago
3 0

Answer:

16/52, or 4/13.

Step-by-step explanation:

First, since we know that the question is asking for the probability of a club <u>or</u> a jack, we know that we have to add the two probabilities. The first probability is that of picking a club, which is 13/52. The probability of picking a jack (be sure not to overlap; don't double count the jack of clubs) is 3/52. Adding these two gives us 13/52+3/52=16/52, which simplifies to 4/13.

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Ilia_Sergeevich [38]

Answer:

C.

Step-by-step explanation:

\frac{2}{3} is between 0 and 1

Only 1 point is between 0 and 1

C.

6 0
2 years ago
Read 2 more answers
3(5a-b) - 2(3a-b) answer step by step​
tiny-mole [99]

Answer:

9a-b

Step-by-step explanation:

1) 3 (5a - b) - 2 (3a - b)

15a - 3b - 2 (3a - b)

2) 15a - 3b - 2 (3a - b)

15a - 3b - 6a + 2b

3) 15a - 3b - 6a + 2b

9a - 3b + 2b

4) 9a + 3b + 2b

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4 0
3 years ago
Jimmy's Bakery sold 950 donuts last week. This week , the number of donuts sold increased 12%. How many more donuts were sold th
Mkey [24]
Step 1: Find 12% of 950
114
Step 2: Add the result to the original number
950 + 114 = 1064
Answer = 114
5 0
2 years ago
I forgot how I check to see if my answer is right :,) can anyone help me ;v; The answer is right I just forgot how to check it​
Novosadov [1.4K]

Answer:

see below

Step-by-step explanation:

To check your solution , plug the value of k into the original equation

6(7k-10) =24

k=2

6(7*2-10) =24

6(14-10) =24

6(4) =24

24=24

The solution is correct

3 0
2 years ago
Pls help me in these two little exercises about the slope.
den301095 [7]

Answer:

3)  y=\dfrac35x+\dfrac25

4) a)  y=-2x+7

  b)  y=\dfrac12x+\dfrac92

Step-by-step explanation:

<u>Exercise 3</u>

-3x + 5y = 2

\implies 5y = 3x + 2

\implies y=\dfrac35x+\dfrac25

<u>Exercise 4</u>

a) If L2 is parallel to L1, it has the same slope (gradient) ⇒ m = -2

If L2 passes through point (3, 1):

y-y_1=m(x-x_1)

\implies y-1=-2(x-3)

\implies y=-2x+7

So L2 = L1

b) If L3 is perpendicular to L1, then the slope of L3 is the negative reciprocals of the slope of L1  ⇒  m = \dfrac12

If L3 passes through point (-5, 2):

y-y_1=m(x-x_1)

\implies y-2=\dfrac12(x+5)

\implies y=\dfrac12x+\dfrac92

4 0
2 years ago
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