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The Keq for the reaction N₂ + 3H2 = 2NH3 if the equilibrium concentrations are Keq = 1.5. The correct option is D.
<h3>What is Keq?</h3>Keq is the ratio of the concentration of reactant to the concentration of the product.
The balanced equation is
N₂ + 3H₂ = 2NH₃
The equilibrium constant is
The given concentrations of the compounds have been:
Ammonia = 3 M
Nitrogen = 1 M
Hydrogen = 2 M
Thus, the correct option is D. Keq = 1.5.
Learn more about Keq
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Answer:
The answer is
Explanation:
The energy of a quantum of light can be found by using the formula
<h3>E = hf</h3>where
E is the energy
f is the frequency
h is the Planck's constant which is
6.626 × 10-³⁴ Js
From the question
f = 4.31 × 10¹⁴ Hz
We have
E = 4.31 × 10¹⁴ × 6.626 × 10-³⁴
We have the final answer as
Hope this helps you
Answer:
220.44g Ba²⁺ ions in solution
Explanation:
Given parameters:
Mass of barium nitrate = 61.2g
Volume of solution = 1 liter
Unkown:
Mass of barium in 7.5quarts of solution?
Solution
We must first convert quarts to its liter equivalence:
1 quarts = 0.95 liter
7.5 quarts = 0.95 x 7.5; 7.125liter
Now, let us find the mass of barium nitrate in a solution of 7.125liter:
Given:
1 liter of solution contains 61.2g of barium nitrate:
7.125 liter will contain 7.125 x 61.2 = 436.05g of barium nitrate.
The formula of the compound is Ba(NO₃)₂:
In solution we have Ba²⁺ + NO₃⁻
Ba(NO₃)₂ → Ba²⁺ + 2NO₃⁻
Number of moles of Ba(NO₃)₂ =
Molar mass of Ba(NO₃)₂ = 137 + 2[14 + 3(16)] = 271g/mol
Number of moles of Ba(NO₃)₂ = = 1.609mole
1 mole of Ba(NO₃)₂ will produce 1 mole of Ba²⁺ ions in solution
therefore, 1.609mole of Ba(NO₃)₂ will also yield 1.609mole of Ba²⁺ ions in solution
Mass of Ba²⁺ ions = Number of moles of Ba²⁺ ions x molar mass of Ba²⁺ ions
Mass of Ba²⁺ ions = 1.609 x 137 = 220.44g