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Goshia [24]
3 years ago
13

What is the conjugate acid in this reaction? HC2H3O2(aq)+H2O(l)⇌H3O++C2H3O−2(aq) View Available Hint(s) What is the conjugate ac

id in this reaction? HC2H3O2 H2O H3O+ C2H3O−2
Chemistry
1 answer:
guapka [62]3 years ago
8 0

Hey there!

HC2H3O2(aq) + H2O(l) → H3O⁺(aq) + C2H3O2⁻(aq)

↓                             ↓              ↓                      ↓

acid                     base             acid            base

If we consider the only forward reaction H3O⁺is the conjugate acid of the base H2O .  For reversse reaction CH3COOH  is the conjugate acid of the base  CH3COO⁻.

Hope this helps!

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State which statement is a physical change or a chemical change:
Oliga [24]

Answer:

Physical change: A,C ,D, F, H, I

Chemical Change: B, E, G, J, K

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There are four different starting molecules that one might use to synthesize the illustrated alkyl halide as the major product u
Mkey [24]

Answer:

Explanation:

An electrophilic addition reaction occurs when an electrophile attacks a substrate, with the end result being the inclusion of one or many comparatively straightforward molecules along with multiple bonds.

In the given question, the hydrogen bromide provides the electrophile while the bromide is the nucleophile. The mechanism proceeds with the attack of the electrophile on the carbon, followed by deprotonation. This process is continued with a formation of carbocation and the bromide(nucleophile) finally bonds to the carbocation to form a stable product.

The first diagram showcases the possible various starting molecules for the synthesis while the second diagram illustrates their mechanism.

6 0
3 years ago
A compound is 2.00% H by mass, 32.7% S by mass, and 65.3% O by mass. What is its empirical
Katarina [22]

Answer:

empirical formula: H_2SO_4

2 g H

32.7 g S

65.3 g O

Explanation:

Like the problem said, the first thing we can do is calculate the mass of each of the 3 elements in a 100-gram sample:

- 2.00% * 100g = 2 g H

- 32.7% * 100g = 32.7 g S

- 65.3% * 100g = 65.3 g O

Now we need to find the empirical formula from these. To do so, convert all of those masses into moles by using the molar mass for each element:

- the molar mass of H is 1.01 g/mol

- the molar mass of S is 32.06 g/mol

- the molar mass of O is 16 g/mol

2 g H ÷ 1.01 g/mol = 1.98 mol H

32.7 g S ÷ 32.06 g/mol = 1.02 mol S

65.3 g O ÷ 16 g/mol = 4.08 mol O

Our ratio of H : S : O is now:

1.98 mol : 1.02 mol : 4.08 mol

Divide them all by the smallest number, which is 1.02:

1.98/1.02  :  1.02/1.02  :  4.08/1.02

1.94 : 1 : 4

1.94 ≈ 2

So:

2 : 1 : 4

Thus, the empirical formula is: H_2SO_4.

7 0
3 years ago
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