First you have to find the intercepts!
To find the y-intercept (I usually do that first), pretend x=0.
Then it becomes:
4(0)-3y=12
Which then becomes:
-3y=12.
Divide both sides, and y = -4.
Then the (x,y) coordinate would become (0, -4).
Next you would find the x-intercept, and pretend y = 0.
Which then becomes:
4x-3(0)=12
3x0 cancels out to become:
4x = 12
And x = 3 because division stuffs.
Then THIS point would then be (3,0).
So then, you would plot (0,-4) and (3,0) on a graph and connect the points! I attached a picture for reference.
hope that helped~
The ball hits the ground when the height h(t) = 0 , so
-16t^2 + 80t = 0
-16t(t - 5) = 0
t- 5 = 0 or -16t^2 = 0 ( here t = 0 which corresponds to when ball is thrown)
t - 5 = 0 gives:-
t = 5 seconds (answer)
-12/3<span>•(-8(-4)^2-6)+2 Original Equation
-12/3</span><span>•(-8+16-6)+2 Simplify the (-4)^2
-12/3</span><span>•(2)+2 Simplify everything inside the equation
-8+2 Using PEMDAS, you multiply -12/3</span><span>•(2)
-6 You add from there</span>
I believe the answer is N+14=72
A unit circle has a radius of 1.
Θ = 600°
1 circle = 360°
Θ = 360° + 240°
(x,y) = cos 360° , sin 240°
(x,y) = -0.50 , -0.886
If these were the given choices:
<span>A.) -(3^(1/2))/2 B.)-1(2^(1/2))/2 C.)-1/2 D.) (3^(1/2))/2
</span>
x = C) - 1/2
y = A) -(3^1/2) / 2