5.2*10^26 molecules of ch4 in volume
1 answer:
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Answer:
18,1 mL of a 0,304M HCl solution.
Explanation:
The neutralization reaction of Ba(OH)₂ with HCl is:
2 HCl + Ba(OH)₂ → BaCl₂ + 2 H₂O
The moles of 17,1 mL≡0,0171L of a 0,161M Ba(OH)₂ solution are:
= 2,7531x10⁻³moles of Ba(OH)₂
By the neutralization reaction you can see that 2 moles of HCl reacts with 1 mole of Ba(OH)₂. For a complete reaction of 2,7531x10⁻³moles of Ba(OH)₂ you need:
= 5,5062x10⁻³moles of HCl.
The volume of a 0,304M HCl solution for a complete neutralization is:
= 0,0181L≡18,1mL
I hope it helps!
Answer: The freezing point and boiling point of the solution are and
respectively.
Explanation:
Depression in freezing point:
where,
= freezing point of solution = ?
= freezing point of water =
= freezing point constant of water =
i = vant hoff factor = 1 ( for non electrolytes)
m = molality
= mass of solute (ethylene glycol) = 21.4 g
= mass of solvent (water) =
= molar mass of solute (ethylene glycol) = 62g/mol
Now put all the given values in the above formula, we get:
Therefore,the freezing point of the solution is
Elevation in boiling point :
where,
= boiling point of solution = ?
= boiling point of water =
= boiling point constant of water =
i = vant hoff factor = 1 ( for non electrolytes)
m = molality
= mass of solute (ethylene glycol) = 21.4 g
= mass of solvent (water) =
= molar mass of solute (ethylene glycol) = 62g/mol
Now put all the given values in the above formula, we get:
Thus the boiling point of the solution is