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butalik [34]
3 years ago
8

5.2*10^26 molecules of ch4 in volume

Chemistry
1 answer:
aivan3 [116]3 years ago
4 0
5.2e+26is it this? im not sure 
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is a way of presenting information about the chemical proportions of atoms

Explanation:

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Describe two ways you could demonstrate an acceleration of 2 meters per second squared?
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You could do 88 metars  

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What is the mass in grams of 0.000142 mol of vitamin c
bazaltina [42]

Answer:

0.0250 g

Explanation:

Step 1: Determine the molar mass of Vitamin C.

The molar mass is the mass in grams corresponding to 1 mole. In order to calculate the molar mass of vitamin C (C₆H₈O₆) we need to add the molar masses of the elements that compose it.

M(C₆H₈O₆) = 6 × M(C) + 8 × M(H) + 6 × M(O)

M(C₆H₈O₆) = 6 × 12.01 g/mol + 8 × 1.01 g/mol + 6 × 16.00 g/mol

M(C₆H₈O₆) =  176.14 g/mol

Step 2: Calculate the mass corresponding to 0.000142 mol of vitamin C.

0.000142 mol \times \frac{176.14g}{mol} =0.0250 g

7 0
3 years ago
Please awnser the fill in blanks don’t mind the top or bottom pls help !!!!
zysi [14]
Can’t see the problems
7 0
2 years ago
What volume of CH4(g), measured at 25oC and 745 Torr, must be burned in excess oxygen to release 1.00 x 106 kJ of heat to the su
anastassius [24]

Answer:

V=27992L=28.00m^3

Explanation:

Hello,

In this case, the combustion of methane is shown below:

CH_4+2O_2\rightarrow CO_2+2H_2O

And has a heat of combustion of −890.8 kJ/mol, for which the burnt moles are:

n_{CH_4}=\frac{-1.00x10^6kJ}{-890.8kJ/mol}= 1122.6molCH_4

Whereas is consider the total released heat to the surroundings (negative as it is exiting heat) and the aforementioned heat of combustion. Then, by using the ideal gas equation, we are able to compute the volume at 25 °C (298K) and 745 torr (0.98 atm) that must be measured:

PV=nRT\\\\V=\frac{nRT}{P}=\frac{1122.6mol*0.082\frac{atm*L}{mol*K}*298K}{0.98atm}\\\\V=27992L=28.00m^3

Best regards.

8 0
3 years ago
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