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3 years ago

5.2*10^26 molecules of ch4 in volume

Chemistry

1 answer:

aivan3 [116]3 years ago

4 0

5.2e+26is it this? im not sure

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Use the concept of natural selection to explain why organisms typically adapt over time.

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3 years ago

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A mixture of gaseous CO and H2, called synthesis gas, is used commercially to prepare methanol (CH3OH), a compound considered an

mr_godi [17]

Answer : The value of equilibrium constant (K) is, 424.3

Explanation : Given,

Concentration of $H_2$ at equilibrium = 0.067 mol

Concentration of $CO$ at equilibrium = 0.021 mol

Concentration of $CH_3OH$ at equilibrium = 0.040 mol

The given chemical reaction is:

$CO+2H_2\rightarrow CH_3OH$

The expression for equilibrium constant is:

$K_c=\frac{[CH_3OH]}{[CO][H_2]^2}$

Now put all the given values in this expression, we get:

$K_c=\frac{(0.040)}{(0.021)\times (0.067)^2}$

$K_c=424.3$

Thus, the value of equilibrium constant (K) is, 424.3

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3 years ago

the atomic number of barium is 56 what do you know about the subatomic particles in an atom of this element

Reptile [31]

Answer is 56 protons and 56 electrons.

<em>Explanation;</em>

Atomic number is equal to number of protons. Hence, when the atomic number is 56, it means that atom has 56 protons.

When the element is in neutral state, number of protons = number of electrons. Hence, we can say that barium atom has 56 electrons.

But same element can have different number of neutrons. Those are called isotopes. Hence, we cannot say that there are 56 neutrons in barium atom without having its mass number. (Mass number = number of protons + number of neutrons)

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Which of the following is NOT a type of joint?

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B. is ur answer I bieleve

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3 years ago

A 155.0 g piece of copper at 128 oC is dropped into 250.0 g of water at 17.9 oC. (The specific heat of copper is 0.385 J/goC.) C

Mamont248 [21]

Answer:

$T_{eq}=23.85^oC$

Explanation:

Hello,

In this case, as the copper's heat loss is gained by the water, the following energetic relationship is:

$\Delta H_{Cu}=-\Delta H_{H_2O}$

Therefore the equilibrium temperature shows up as:

$m_{Cu}Cp_{Cu}(T_{Cu}-T{eq}) = m_{H_2O}Cp_{H_2O}(T_{eq}-T_{H_2O})\\\\T_{eq}=\frac{m_{Cu}Cp_{Cu}T_{Cu}-m_{H_2O}Cp_{H_2O}T_{H_2O}}{m_{Cu}Cp_{Cu}-m_{H_2O}Cp_{H_2O}} \\$

Thus, by knowing that water's heat capacity is 4.18J/g°C, one obtains:

$T_{eq}=\frac{155.0g*0.385\frac{J}{g^oC}*128^oC+250.0g*4.18\frac{J}{g^oC}*17.9^oC}{155.0g*0.385\frac{J}{g^oC}+250.0g*4.18\frac{J}{g^oC}}=23.85^oC$

Best regards.

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