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maksim [4K]
3 years ago
12

Graphite crystals can be used as a lubricant. TRUE FALSE

Physics
2 answers:
timurjin [86]3 years ago
6 0
I think its true because they are a soft solid that can be broken down into a liquid... Hope this helps in any way :3
Murrr4er [49]3 years ago
4 0
 <span>Graphite and Diamond are allotropes of Carbon meaning they have the same chemical properties of carbon (they both burn, yes diamond burns. At 1500 Celcius), but totally different physical properties. Graphite is a good conductor of both electricity and heat, Diamond isn't. Graphite is slippery, Diamond isn't. Graphite is soft, diamond is hard. Diamond is transparent, graphite is a black powder. 

The reason for this is that the lattice structure( geometrical arrangement of carbon atoms in the crystal) of G and D are vastly different (hence different physical propetries), but they are basically the same element(hence the same chemical properties.) 

Graphite has what is known as a Hexagonal Lattice Structure. Imagine a thin slice of a honeycomb placed at a certain distance over another slice, which in turn is placed over the next and so on, with each vertex of each hexagon representing a carbon atom. This is what the graphite crystal structure looks like. Now, the layers of the lattice are bound to the adjacent layers by weak Van der Waals bonds, which allow the layers to slide over one another easily, like a teetering pile of paper sheets. Hence you get the quintessential properties of Graphite - softness, slipperiness and hence it makes an excellent solid lubricant. 

Diamond, on the other hand has a tetrahedral "diamond" structure, in which carbon atoms are held rigidly by neighbouring atoms by powerful bonds that require a great deal of force to be broken. Hence Diamond is hard, strong and can be used as an abrasive to grind and polish other materials.... 

So to answer your question its True

</span>
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A jet plane comes in for a downward dive as shown in the figure below.
xxTIMURxx [149]

The solution would be like this for this specific problem:

<span>5.5 g = g + v^2/r </span><span>
<span>4.5 g = v^2/r </span>
<span>v^2 = 4.5 g * r </span>
<span>v = sqrt ( 4.5 *9.81m/s^2 * 350 m) </span>
v = 124 m/s</span>

So the pilot will black out for this dive at 124 m/s. I am hoping that these answers have satisfied your query and it will be able to help you in your endeavors, and if you would like, feel free to ask another question.

8 0
3 years ago
Read 2 more answers
Why not two magnetic field lines can intersect? why not it is possible?
11111nata11111 [884]
At each point on a 'line', the direction of the 'line' is the direction of the force
on a small test magnet placed in the field at that point.

If two 'lines' crossed at the same point, that means a small test magnet placed
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But even if that were true, then the net effect on the small test magnet would be
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4 0
4 years ago
What is the mass of the cube<br> Density is 40 g/cm3<br> Length of the side= 2 cm
Andrej [43]

Answer:

80

Explanation:

because of the denstiy formula

4 0
3 years ago
I don’t know the answer to 4395g=________kg
monitta
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5 0
4 years ago
Read 2 more answers
A loop of wire in the shape of a rectangle rotates with a frequency of 143 rotation per minute in an applied magnetic field of m
tatiyna

Answer:

1. e m fmax = 0.00598 Volt

2. Imax = 0.000854 Amp

Explanation:

1. Find the maximum induced emf.

e m fmax =

Given that e m fmax = N*A*B*w

N = 1

A = 2 cm^2 = 0.0002 m^2

f = 143 rotation per minute = 143/min

f = (143/min) * (1 min/60 sec) = 2.38/sec

w = 2Πf = 2 * Π * 2.38 = 14.95 rad/sec

B = 2T

e m fmax = N*A*B*w

e m fmax = 1 * 0.0002 * 2 * 14.95

e m fmax = 0.00598 Volt.

2. Find the maximum current through the bulb.

Imax = e m fmax / R

Where R is the total resistance in the circuit is 7 Ω.

Imax = 0.00598/7 = 0.000854 Amp.

Imax = 0.000854 Amp

6 0
3 years ago
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