All categories

3 years ago

PLEASE HELP ASAP

Chemistry

2 answers:

Naddika [18.5K]3 years ago

6 0

C evaporating water is the answer

blagie [28]3 years ago

3 0

Answer:

evaporating water

Explanation:

You might be interested in

At sea level, where the pressure was 104 kPa and temperature 21.1 ºC, a certain mass of air occupies 2.0 m3 . To what volume wil

Romashka [77]

Answer:

The volume of air at where the pressure and temperature are 52 kPa, -5.0 ºC is $3.64 m^3$ .

Explanation:

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 104 kPa

$P_2$ = final pressure of gas = 52 kPa

$V_1$ = initial volume of gas = $2.0m^3$

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $21.1^oC=273+21.1=294.1K$

$T_2$ = final temperature of gas = $-5.0^oC=273+(-5.0)=268 K$

Now put all the given values in the above equation, we get:

$\frac{104 kPa\times 2.0m^3}{294.1 K}=\frac{52 kPa\times V_2}{268 K}$

$V_2=3.64 m^3$

The volume of air at where the pressure and temperature are 52 kPa, -5.0 ºC is $3.64 m^3$ .

3 0

2 years ago

What is the molar mass of Sn(CO3)2?

Free_Kalibri [48]

Answer:

The molar mass and molecular weight of Sn(CO3)2 is 238.728.

Explanation:

7 0

2 years ago

How many atoms are in 578g Na

borishaifa [10]

1.51 x 10²⁵atoms

Explanation:

Given parameters:

Mass of Na = 578g

Unknown:

Number of atoms = ?

Solution:

To find the number of atoms, we must first find the number of moles the given mass contains.

Number of moles = $\frac{mass}{molar mass}$

molar mass of Na = 23g

Number of moles = $\frac{578}{23}$ = 25.13moles

1 mole of a substance = 6.02 x 10²³atoms

25.13 mole of Na = 25.13 x 6.02 x 10²³atoms

This gives 1.51 x 10²⁵atoms of Na

Learn more:

Avogadro's constant brainly.com/question/2746374

#learnwithBrainly

5 0

3 years ago

Given the following reaction: NH4SH (s) <--> NH3 (g) + H2S (g) If we start

almond37 [142]

Answer:

D. 0.3 M

Explanation:

NH4SH (s) <--> NH3 (g) + H2S (g)

Initial concentration 0.085mol/0.25L 0 0

Change in concentration -0.2M +0.2 M +0.2M

Equilibrium 0.035mol/0.25 L=0.14M 0.2M 0.2M

concentration

Change in concentration (NH4SH) = (0.085-0.035)mol/0.25L =0.2M

K = [NH3]*[H2S]/[NH4SH] = 0.2M*0.2M/0.14M ≈ 0.29 M ≈ 0.3M

4 0

3 years ago

______is the condition of the atmosphere at any given time and place and ______is the weather over a long period of time (fill i

Nady [450]

Answer:

Temperature is the condition of the atmosphere at any given time and place

and climate is the weather over a long period of time

Explanation:

I think so-

7 0

3 years ago