Decomposition is a chemical reaction that breaks the reactant into two or more products. Moles of nitrogen gas 
in the cylinder is 1.63 moles.
<h3>What is the ideal gas equation?</h3>
The ideal gas equation states the relation of the hypothetical ideal gas according to the pressure, volume, temperature and moles of the gas. It is given by,
Where,
Pressure (P) = 2000 kPa
Volume (V) = 2L
Temperature (T) = 295 K
Gas constant (R)= 0.08206
Substituting values in the equation:
Therefore, 1.63 moles are produced.
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The name of the configuration management procedure that involves the collection of information about a system under normal operating conditions is Baselining.
<h3>What is Baselining?</h3>
Baselining is a management process used to analyze a collection of information about a particular system.
This procedure (Baselining) is well known to analyze computer performance in a given network.
In conclusion, the name of the configuration management procedure that involves the collection of information about a system under normal operating conditions is Baselining.
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<span>Friction creates heat which in turn can lead to deviations from the original size and shape of a part.
</span>
1.<span>B) <span>the subscript
2.<span>B)<span>CO2 </span></span>.
3.B) potential energy is converted into kinetic energy
4.A) A roller coaster at the top of a hill
6.C) in motion
7.D) weed whacker full of gas
8.B) potential energy only
9.</span></span>A) baking soda
1. The empirical formula of the hydrocarbon is CH₃
2. The molecular formula of the hydrocarbon is C₂H₆
<h3>How to determine the mass of Carbon </h3>
- Mass of CO₂ = 1.47 g
- Molar mass of CO₂ = 44 g/mol
- Molar of C = 12 g/mol
- Mass of C =?
Mass of C = (12 / 44) × 1.47
Mass of C = 0.4 g
<h3>How to determine the mass of H</h3>
- Mass of compound = 0.5 g
- Mass of C = 0.4 g
- Mass of H = ?
Mass of H = (mass of compound) – (mass of C)
Mass of H = 0.5 – 0.4
Mass of H =0.1 g
<h3>1. How to determine the empirical formula </h3>
- C = 0.4 g
- H = 0.1 g
- Empirical formula =?
Divide by their molar mass
C = 0.4 / 12 = 0.03
H = 0.1 / 1 = 0.1
Divide by the smallest
C = 0.03 / 0.03 = 1
H = 0.1 / 0.03 = 3
Thus, the empirical formula of the compound is CH₃
<h3>2. How to determine the molecular formula</h3>
- Empirical formula = CH₃
- Molar mass = 30 g/mol
- Molecular formula =?
Molecular formula = empirical × n = mass number
[CH₃]n = 30
[12 + (3×1)]n = 30
15n = 30
Divide both side by 15
n = 30 / 15
n = 2
Molecular formula = [CH₃]n
Molecular formula = [CH₃]₂
Molecular formula = C₂H₆
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