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MArishka [77]
3 years ago
8

Give the empirical formula for C↓8H↓8

Chemistry
1 answer:
mr_godi [17]3 years ago
4 0

Answer:

Empirical formula of  C₈H₈ =  CH

Explanation:

Data Given:

Molecular Formula = C₈H₈

Empirical Formula = ?

Solution

Empirical Formula:

Empirical formula is the simplest ration of atoms in the molecule but not all numbers of atoms in a compound.

So,

tha ration of the molecular formula should be divided by whole number to get the simplest ratio of molecule

        C₈H₈ Consist of  Carbon (C), and Hydrogen (H)

Now

Look at the ratio of these two atoms in the compound

                         C : H

                         8 : 8

Divide the ratio by two to get simplest ratio

                          C : H

                       8/8 : 8/8

                         1   :  1

So for the empirical formula is the simplest ratio of carbon to hydrogen 1 : 1

So the empirical formula will be

                     Empirical formula of  C₈H₈ =  CH

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polet [3.4K]

Answer:

12.09 L

Explanation:

Step 1: Convert 826.1 mmHg to atm

We will use the conversion factor 760 mmHg = 1 atm.

826.1 mmHg × 1 atm/760 mmHg = 1.087 atm

Step 2: Convert 427.8 J to L.atm

We will use the conversion factor 101.3 J = 1 L.atm.

427.8 J × 1 L.atm/101.3 J = 4.223 L.atm

Step 3: Calculate the change in the volume

Assuming the work done (w) is 4.223 L.atm against a pressure (P) of 1.087 atm, the change in the volume is:

w = P × ΔV

ΔV = w/P

ΔV = 4.223 L.atm/1.087 atm = 3.885 L

Step 4: Calculate the final volume

V₂ = V₁ + ΔV

V₂ = 8.20 L + 3.885 L = 12.09 L

5 0
3 years ago
Answer?????????????????????????????!!?!?!?!,!?!?!?
aniked [119]

Answer:

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Explanation:

this makes sense to me but im not sure.

8 0
3 years ago
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How many moles of NH3 can be produced by the reaction of 2.00 g of N2 with 3.00 g H2?
yulyashka [42]
0.235 if I’m not mistaken!
8 0
3 years ago
How many grams are in 4.5 x 10^22 molecules of Ba(NO2)2
NNADVOKAT [17]

Answer:

17 g Ba(NO₂)₂

General Formulas and Concepts:

<u>Chemistry</u>

  • Stoichiometry
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

4.5 × 10²² molecules Ba(NO₂)₂

<u>Step 2: Define conversion</u>

Molar Mass of Ba - 137.33 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Ba(NO₂)₂ - 137.33 + 2(14.01) + 4(16.00) = 229.35 g/mol

<u>Step 3: Dimensional Analysis</u>

<u />4.5 \cdot 10^{22} \ mc \ Ba(NO_2)_2(\frac{1 \ mol \ Ba(NO_2)_2}{6.022 \cdot 10^{23} \ mc \ Ba(NO_2)_2} )(\frac{229.35 \ g \ Ba(NO_2)_2}{1 \ mol \ Ba(NO_2)_2} )

= 17.1384 g Ba(NO₂)₂

<u>Step 4: Check</u>

<em>We are given 2 sig figs. Follow sig fig rules.</em>

17.1384 g Ba(NO₂)₂ ≈ 17 g Ba(NO₂)₂

7 0
3 years ago
Show the calculation of the molar mass (molecular weight) of a solute if a solution of 5.8 grams of the solute in 100 grams of w
Leni [432]

Answer : The molar mass of solute is, 89.9 g/mol

Explanation : Given,

Mass of solute = 5.8 g

Mass of solvent (water) = 100 g

Formula used :  

\Delta T_f=K_f\times m\\\\T_f^o-T_f=T_f\times\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of water}}

where,

\Delta T_f = change in freezing point

T_f^o = temperature of pure solvent (water) = 0^oC

T_f = temperature of solution = 1.20^oC

K_f = freezing point constant of water = 1.86^oC/m

m = molality

Now put all the given values in this formula, we get

(0^oC)-(1.20^oC)=1.86^oC/m\times \frac{5.8g\times 1000}{\text{Molar mass of solute}\times 100g}

\text{Molar mass of solute}=89.9g/mol

Therefore, the molar mass of solute is, 89.9 g/mol

5 0
3 years ago
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