Answer:
The first one is synthesis
The answer is C.
Since KOH and MgCl2 are in a 2:1 ratio, the moles of MgCl2 formed will always be half of the moles of KOH. The only answer where moles of KOH are halved is option C
Glucose freezes at -3.75 °C and freezing point of pure water is 0 °C. Thus, depression in freezing point or can be calculated as follows:
It is related to molal concentration as follows:
Here, is freezing point depression constant.
Rearranging to calculate molal concentration:
Therefore, molal concentration of glucose in the solution will be 2.02 m.
Don’t really know what it is just need points end