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3 years ago

1/4 x + 1/6 x = x-7.

Mathematics

1 answer:

weeeeeb [17]3 years ago

5 0

Answer:

x=12

Step-by-step explanation:

Simplify both sides by adding like terms

5/12x=x-7

subtract x from both sides

-7/12x=-7

multiply both sides by 12/-7

x=12

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julsineya [31]

After h hours Cary makes 5h dollars so after paying mom has

5h - 6

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3 years ago

Which of the following is true?

Dahasolnce [82]

Answer:

the right ones are a c and d maybe

Step-by-step explanation:

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2 years ago

By what percent will a fraction decrease if its numerator is increased by 20% and its denominator is increased by 50%?

Brums [2.3K]

Lets find out...

our fraction is 1/2.....
when the numerator is increased by 20%......1 + 0.20(1) = 1.2
when the denominator is increased by 50%....2 + 0.50(2) = 3

1/2 = 0.5....original fraction
1.2 / 3 = 0.4.....increased fraction

decrease = (original number - new number) / original number...* 100
= (0.5 - 0.4) / 0.5...* 100
= (0.1 / 0.5)....* 100
= 0.2 * 100
= 20% decrease <====

3 0

2 years ago

Read 2 more answers

Find the value of the variable and MN if N is between M and Q. Round to the nearest hundredth if necessary.

Rudiy27

Answer:
MN = 4 units

Explanation:
1- getting the value of m:
We are given that:
NQ = 4m and NQ = 12
This means that:
12 = 4m
$\frac{4m}{4} = \frac{12}{4}$
m = 3

2- getting MQ:
We are given that:
MQ = 5m + 1
We have calculated that:
m = 3
Therefore:
MQ = 5(3) + 1 = 15 + 1 = 16 units

3- getting MN:
We are given that point N is located somewhere between points M and Q.
This means that:
line MQ can be divided into two portions: MN and NQ
This also means that:
length of MQ = length of MN + length of NQ

We have calculated that:
MQ = 16 units
We are given that:
NQ = 12 units
Therefore:
16 = length of MN + 12
length of MN = 16 - 12
length of MN = 4 units

Hope this helps :)

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3 years ago

Can you always use grouping to factor

Softa [21]

Answer:

Step-by-step explanation:

it's not always possible to factor a quadratic expression of this factoring by grouping. The method doesn't work when an expression cannot be factored as (Ax+B)(Cx+D) where A, B, C and D are integrers.

In that case, you should use other methods.

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3 years ago

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