(a)
consider the motion of the tennis ball. lets assume the velocity of the tennis ball going towards the racket as positive and velocity of tennis ball going away from the racket as negative.
m = mass of the tennis ball = 60 g = 0.060 kg
v₀ = initial velocity of the tennis ball before being hit by racket = 20 m/s
v = final velocity of the tennis ball after being hit by racket = - 39 m/s
ΔP = change in momentum of the ball
change in momentum of the ball is given as
ΔP = m (v - v₀)
inserting the above values
ΔP = (0.060) (- 39 - 20)
ΔP = - 3.54 kgm/s
hence , magnitude of change in momentum : 3.54 kgm/s
The wavelength decreases to roughly half.
(The frequency roughly doubles.)
The answer for the question is bandwagon. Hope it helped :)
A bicyclist moving at a constant speed takes 10.0 seconds to travel 500 meters down a path inclined 30.0° downward from the horizontal. the vertical velocity of this motion is mathematically given as
V' = 25 m/s. Option C.
<h3>What is the vertical velocity of this motion?</h3>
Generally, the equation for the Inclined Component is mathematically given as
V=d/s
Therefore
V = 500/10
V= 50 m/s
In conclusion, for the vertical Component

V'= 50Sin30
V' = 25 m/s
Read more about Motion
brainly.com/question/605631
#SPJ1