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Elza [17]
3 years ago
12

a car travels from station A to B at 30kmph during its return trip A it travels 30 km pH for the first half distance and it 70 k

mph for half next half distance find the average speed of the car​
Physics
1 answer:
8_murik_8 [283]3 years ago
3 0

Explanation:

If you cannot visualize it, just assume that the distance from station A to B is 420km. Each half is 210km.

When the car travels from A to B, it takes 420/30 = 14 hours.

When the car travels from B to the halfway point, it takes 210/30 = 7 hours.

When the car travels from the halfway point to A, it takes 210/70 = 3 hours.

Total time taken = 14 + 7 + 3 = 24 hours.

Total distance = 420km * 2 = 840km.

Hence, the average speed of the car is 840/24 = 35km/h.

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Please help me - i beg u
oksano4ka [1.4K]

Answer:

516526.863 m

Explanation:

From the question given above, the following data were obtained:

Acceleration due to gravity (g) = 2.24 m/s²

Mass (M) = 8.96×10²¹ Kg

Gravitational constant (G) = 6.67×10¯¹¹Nm²/Kg²

Radius (r) =?

The radius of the planet can be obtained as follow:

g = GM/r²

2.24 = 6.67×10¯¹¹ × 8.96×10²¹ / r²

2.24 = 5.97632×10¹¹ / r²

Cross multiply

2.24 × r² = 5.97632×10¹¹

Divide both side by 2.24

r² = 5.97632×10¹¹ / 2.24

r² = 2.668×10¹¹

Take the square root of both side

r = √2.668×10¹¹

r = 516526.863 m

Thus, the radius of the planet is 516526.863 m

8 0
3 years ago
A car mass 600kg starts from rest moving uniform acceleration 0.2 m/s^2 after 60 seconds collides with stationary pick up van of
nlexa [21]

Answer:

The given phenomenon  supports the Principle of Conservation of momentum.

Explanation:

law of conservation of momentum  

Initial Momentum = Final Momentum

So, first we calculate initial momentum of the system:

Initial Momentum  = m1*u1 + m2*u2

and we are given

m1 = mass of car = 600 kg

m2 = mass of van = 400 kg

u1 = Initial Speed of Car  

to find the initial speed we use equation of motion

Vf = Vi + at

Vf = 0 m/s + (0.2 m/s²)(60 s)

Vf = u₁ = 12 m/s  

u₂ = Initial Speed of Van = 0 m/s

Therefore,

Initial Momentum  = (600 kg)(12 m/s) + (400 kg)(0 m/s)

Initial Momentum  = 7200 Ns   .........(1)

final momentum = m₁v₁ + m₂v₂

where,

v₁ = v₂ = final speed of car+van (both locked ) = 7.2 m/s

Therefore,

Final Momentum = (600 kg)(7.2 m/s) + (400 kg)(7.2 m/s)

Final Momentum = 7200 Ns   -------- (2)

on comparing (1) and (2)

Initial momentum = Final Momentum

Hence, the phenomenon of the system supports the principle of conservation of momentum.

6 0
3 years ago
A layer of ethyl alcohol (n= 1.361) is on top of the water ( n=1.333) . At what angle relative to the normal to the interface of
hram777 [196]

Answer:

78.35°

Explanation:

THIS IS THE COMPLETE QUESTION BELOW;

A layer of ethyl alcohol (n = 1.361) is on top of water (n = 1.333). To the nearest degree, at what angle relative to the normal to the interface of the two liquids is light totally reflected?

From Snell's Law,

(ni)/(nr) = Sin (θr) / Sin (θi)

Where

θi = Angle of Incidence

θr = Angle of refraction

ni = Refractive index given for ethyl alcohol

nr = Refractive index of medium from which light is refracted

ni = 1.361

nr = 1.333

, θr = 90° ( Critical Angle is reffered to as Angle of Incidence at refracted angle of 90°) (θi = θc)

(ni)/(nr) = Sin (θr) / Sin (θi)

1.361/ 1.333 = Sin (90°)/ Sin( θc)

1.021= 0.894/ Sin( θc)

Sin( θc)= (0.9794

θc = Sin⁻¹ 0.9794)

θc = 78.35°

7 0
3 years ago
Help me with this please <br>​
Rina8888 [55]

Answer:

Where is the Question?

Explanation:

I am glad to h help you out.

6 0
3 years ago
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uysha [10]
It's choice A and B. PE=mgh
5 0
3 years ago
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