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scoundrel [369]
3 years ago
13

Someone please help me

Physics
1 answer:
mars1129 [50]3 years ago
8 0

The answer is parallel

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A space rocket accelerates uniformly from rest to 160ms^-1 upwards in 4.0s, then travels with a constant speed of 160ms^-1 for t
ivann1987 [24]

Answer:

40 ms¯².

Explanation:

To solve this problem, we shall illustrate the question with a diagram.

The attached photo gives a better understanding of the question.

From the attached photo:

Velocity (v) = 160 ms¯¹

Time (t) = 4 secs.

Acceleration (a) =?

Acceleration (a) = Velocity (v) /time (t)

a = v/t

a = 160/4

a = 40 ms¯²

Therefore, the initial acceleration of the rocket is 40 ms¯².

5 0
3 years ago
Cindy rides her bike
Cloud [144]

Answer:

its 30 i did this homeweok

Explanation:

30

3 0
3 years ago
Read 2 more answers
Help ;-;
nasty-shy [4]

Answer:

all qn 1,2,3 have same answer ,. Yes,. hope it helps

3 0
3 years ago
Three identical very dense masses of 7500 kg each are placed on the x axis. One mass is at x1 = -100 cm , one is at the origin,
sukhopar [10]

Answer:

0.00354 (N)

Explanation:

Convert to metric system:

x_1 = -100 cm = 1 m

x_2 = 420 cm = 4.2 m

Formula for gravitational force:

F_g = G\frac{mM}{s^2}

where s is the distance between 2 bodies masses m and M

Substitute the number to the formula above and since the 2 forces are acting in opposite direction, the total net gravitational force on the mass of origin be:

F_g = F_{g1} - F_{g2}

F_g = G\frac{m_1M}{x_1^2} - G\frac{m_2M}{x_2^2}

F_g = GM(\frac{m_1}{x_1^2} - \frac{m_2}{x_2^2})

F_g = 6.67*10^{-11} * 7500 (\frac{7500}{1^2} - \frac{7500}{4.2^2})

F_g = 5*10^{-7}(7500 - 425.17)

F_g = 5*10^{-7} * 7074.83

F_g = 0.00354 (N)

5 0
3 years ago
A current of 4 amps is running through a circuit with a resistance of 2ohms.What is the voltage.Show working
Rufina [12.5K]
Voltage = current * resistance
V = I*R
I = 4 A
R = 2 ohm
V = 4 A * 2 ohm
= 8 volt
7 0
3 years ago
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