Answer:
7.1 J
Explanation:
From the question,
Work done by the mover = work done in pushing the crate + work done against friction
W = W'+Wf................. Equation 1
W = mgd+mgμd............ Equation 2
W = mgd(1+μ)................ Equation 3
Where m = mass of the crate, g = acceleration due to gravity, d = distance, μ = coefficient of friction.
Given: m = 46 kg, d = 10.5 mm = 0.0105 m, μ = 0.5
constant: g = 9.8 m/s²
Substitute these values into equation 3
W = 46×9.8×0.0105(1+0.5)
W = 7.1 J
Answer:
The angular momentum of the wheel is .
Explanation:
It is given that,
Mass of the wheel, m = 2.73 kg
Radius of the wheel, r = 31 cm = 0.31 m
Angular speed of the wheel,
We need to find its angular momentum. It is given by :
I is the moment of inertia of the wheel,
So, the angular momentum of the wheel is . Hence, this is the required solution.
I think the best would be B my friend
Answer:
you can simply answer by derivative = 3.5x^2+25x+250-y=0 you can derivate this eqn 7x +25-1=0 7x=24 yo u can divide you get it