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Misha Larkins [42]
3 years ago
13

The ph of 0.255 m hcn is 4.95. What is the value of ka for hydrocyanic acid?

Chemistry
1 answer:
Lera25 [3.4K]3 years ago
5 0

Answer:

Ka = 4.9 X 10^-9

Explanation:

when the pH  is 4.95

the [H+] = 10^-4.95

[H+] = 1.122 e-5

since the equilibrium equation is:

HCN <=> 1 mole H+  &  1 mole CN-

then

[H+] = [CN-]

when

HCN <=>  H+  &   CN-

Ka = [ H+]  [CN-]  / [HCN]

Ka = [ 1.122 e-5]  [ 1.122 e-5]  / [0.255]

Ka = 1.256 e-10 / 0.255

Ka = 4.94 e-9

which rounds off to 2 sig figs into

Ka = 4.9 X 10^-9

======================

p.s. it was the pH pf 4.95 that limited the calculations to 2 sig figs

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How many moles of Fe2O3 are in 203 g of the compound?
ruslelena [56]
The equation is :
moles=mass/molar mass
so, the mass is 203 and molar mass is 159.69 
You divide the 203 by 156.69 as the equation shows
so the moles is 1.27 mol. 
6 0
3 years ago
13) Find the mass, in grams, of 5.75 liters of N2.
faltersainse [42]
Molecular weight of N2
gram Atomic weight of N is 14 g.
gram Molecular weight = 14 g×2
= 28 g
Liter concepts
1 liter of gas always occupies 1 gram molecular weight .
Application of the concept
5.75 liter gives 0.257g


1 mole will occupy 28 g

0.257 will occupy 28 g × 0.257
= 7.196 g

The mass of the gas is 7.196 g.

Hope it helps you
8 0
3 years ago
When an atom is in the ground state what must happen for the atom to be in an excited state? what must happen for this atom to r
scoray [572]
Hi there

In order for an electron to jump into a higher energy state, it must first absorb energy (heat, light, etc).

When an electron goes back down to the ground state from the excited state, it emits energy usually in the form of a photon.

i hope this helps

4 0
3 years ago
The acid-dissociation constants of HC3H5O3 and CH3NH3+ are given in the table below. Which of the following mixtures is a buffer
sergey [27]

Answer:

A mixture of 100. mL of 0.1 M HC3H5O3 and 50. mL of NaOH

Explanation:

The pH of a buffer solution is calculated using following relation

pH=pKa+log(\frac{salt}{acid} )

Thus the pH of buffer solution will be near to the pKa of the acid used in making the buffer solution.

The pKa value of HC₃H₅O₃ acid is more closer to required pH = 4 than CH₃NH₃⁺ acid.

pKa = -log [Ka]

For HC₃H₅O₃

pKa = 3.1

For CH₃NH₃⁺

pKa = 10.64

pKb = 14-10.64 = 3.36 [Thus the pKb of this acid is also near to required pH value)

A mixture of 100. mL of 0.1 M HC3H5O3 and 50. mL of NaOH

Half of the acid will get neutralized by the given base and thus will result in equal concentration of both the weak acid and the salt making the pH just equal to the pKa value.

8 0
3 years ago
A gas is at 35.0°c and 3.50 l. what is the temperature at 7.00 l?
Degger [83]

Answer:

363C

Explanation:

V = KT  and T = V/K

3.5=k(35+273) = 308k

k=3.5/308 =0.011

new T=7.0/0.011=636K = 636-273 =363C

4 0
2 years ago
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