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kramer
3 years ago
11

Chemical equilibrium occurs when the rates of the reactions

Chemistry
1 answer:
Flura [38]3 years ago
6 0
Chemical equilibrium is a state where the rate of forward reaction is equal to the rate of the backward reaction. The answer of this problem is D.
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A hydrogen bond is Select one: a. an attractive force that usually involves a polarly-bonded hydrogen atom and another polarly-b
Liula [17]

Answer: answer is a) an attractive force that usually involves a polarly-bonded hydrogen atom and another polarly-bonded atom with a partial negative charge

Explanation: hydrogen bond is a special type of bonding that closely resembles an ionic bond. It involves hydrogen atom and another highly electronegative atom, this bond is due to the the attraction between the slight positive charge on the hydrogen and the slight negative charge on the pairing atom.

Note that electron is not transfered as in ionic bonding.

Molucules with hydrogen bonding between their atoms includes water, hydrogen fluoride and ammonia.

4 0
3 years ago
The solubility product constant of pbcl2 is 1.7 × 10−5 . what is the maximum concentration of pb2+ that can be in ocean water th
Sunny_sXe [5.5K]
Answer is: the maximum concentration of Pb²⁺ is 6.8·10⁻³ M.
Chemical reaction 1: PbCl₂(s) → Pb²⁺(aq) + 2Cl⁻(aq).
Chemical reaction 2: NaCl(aq) → Na⁺(aq) + Cl⁻(aq).
Ksp(PbCl₂) = 1.7·10⁻⁵.
c(NaCl) = c(Cl⁻) = 0.0500 M.
Ksp(PbCl₂) = c(Pb²⁺) · c(Cl⁻)².
c(Pb²⁺) = Ksp(PbCl₂) ÷ c(Cl⁻)².
c(Pb²⁺) = 1.7·10⁻⁵ M³ ÷ (0.0500 M)².
c(Pb²⁺) = 0.000017 M³ ÷ 0.0025 M².
c(Pb²⁺) = 0.0068 M = 6.8·10⁻³ M.

3 0
3 years ago
Write the ion-product expression at equilibrium for each compound: How to enter the correct answer: e.g. silver sulfate (Ag2SO4)
enot [183]

Answer:

(1) Magnesium carbonate :-

Q_{MgCO_3}=[Mg^{2+}][CO_3^{2-}]

(2) Calcium phosphate :-

Q_{Ca_3(PO_4)_2}=[Ca^{2+}^3][PO_4^{3-}^2]

(3) Silver sulfide :-

Q_{Ag_2S}=[Ag^{+}^2][S^{2-}]

Explanation:

(1) Magnesium carbonate will dissociate as:-

MgCO_3\rightarrow Mg^{2+}+CO_3^{2-}

The expression for the ion-product is as follows:-

Q_{MgCO_3}=[Mg^{2+}][CO_3^{2-}]

(2) Calcium phosphate will dissociate as:-

Ca_3(PO_4)_2\rightarrow 3Ca^{2+}+2PO_4^{3-}

The expression for the ion-product is as follows:-

Q_{Ca_3(PO_4)_2}=[Ca^{2+}^3][PO_4^{3-}^2]

(3) Silver sulfide will dissociate as:-

Ag_2S\rightarrow 2Ag^{+}+S^{2-}

The expression for the ion-product is as follows:-

Q_{Ag_2S}=[Ag^{+}^2][S^{2-}]

6 0
3 years ago
Numero de oxidacion <br> Fe + O2=Fe2O3
nexus9112 [7]

Fe =0

O2 =0

Fe in Fe2O3 =+3

O in Fe2O3=-2

7 0
3 years ago
I need help with this right now
Ira Lisetskai [31]

Answer:

do it on your own

Explanation:

hahahaha

7 0
4 years ago
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