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3 years ago

3.264g of zonic chloride and 1.468g of zinc metal how much zinc obtained? Was all zinc possible from the recovery?

Chemistry

1 answer:

scoray [572]3 years ago

5 0

3.264 g of ZnCl2 is 0.02394 moles. From the formula for ZnCl2, this is also the moles of Zn you should have gotten.

Atomic mass of Zn = 1.565 g is the theoretical yield you should have gotten

percent recovery = 1.468 g / 1.565 g * 100

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$\\ \sf\longmapsto CaCO_3$

$\\ \sf\longmapsto 40u+12u+3(16u)$

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3 years ago

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3) During the day at 27°C a cylinder with a sliding top contains 20.0 liters

tatiyna

Answer:

$T_2=12\°C$

Explanation:

Hello there!

In this case, according to the Charles' law equation which help us to understand the directly proportional relationship between volume and temperature:

$\frac{T_2}{V_2}=\frac{T_1}{V_1}$

Thus, by solving for the final temperature, T2, and making sure we use the temperatures in Kelvin, we can calculate the final temperature as shown below:

$T_2=\frac{T_1V_2}{V_1} \\\\T_2=\frac{(27+273)K*19L}{20.0L}\\\\T_2=285-273\\\\T_2=12\°C$

Best regards!

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