The volume (in liters) that the gas will occupy if the pressure is increased to 13.5 atm and the temperature is decreased to 15 °C is 15 L
From the question given above, the following data were obtained:
Initial pressure (P₁) = 8.5 atm
Initial volume (V₁) = 24 L
Initial temperature (T₁) = 25 °C = 25 + 273 = 298 K
Final pressure (P₂) = 13.5 atm
Final temperature (T₂) = 15 °C = 15 + 273 = 288 K
<h3>Final volume (V₂) =? </h3>
- The final volume of the gas can be obtained by using the combined gas equation as illustrated below:
Cross multiply
298 × 13.5 × V₂ = 204 × 288
4023 × V₂ = 58752
Divide both side by 4023
<h3>V₂ = 15 L </h3>
Therefore, the final volume of the gas is 15 L
Learn more: brainly.com/question/25547148
Answer:
Two Sections that contain nitrogen of a nucleotide that bond together to connect strands of DNA or RNA.
Explanation:
Molecular Motion<span> is the speed at which molecules or atoms move dependent on temperature and state of matter.
Explanation:
</span>All molecules are<span> in constant motion. Molecules of a liquid have </span>a lot of<span> freedom of movement than those </span>in an exceedingly<span> solid. Molecules </span>in an exceedingly<span> gas have </span>the best<span> degree of motion.</span>
<span>
Heat, temperature </span>and also the<span> motion of molecules </span>area unit<span> all </span>connected<span>. Temperature </span>could be a life<span> of </span>the common K.E.<span> of the molecules </span>in an exceedingly<span> material. Heat </span>is that the<span> energy transferred between materials that have </span>completely different temperatures<span>. Increasing the temperature </span>will increase<span> the </span>travel<span> motion of molecules Energy </span>is expounded<span> to temperature by the relationship.</span>
Answer:
T₂ = 150 K
Explanation:
Given data:
Initial volume of gas = 804 mL
Initial temperature = 27°C (27+273=300 K)
Final temperature = ?
Final volume = 402 mL
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
T₂ = V₂T₁/V₁
T₂ = 402 mL × 300 K / 804 mL
T₂ = 120,600 mL.K / 804 mL
T₂ = 150 K
