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Alchen [17]
4 years ago
14

How does ionization energy change from left to right on a period?

Chemistry
1 answer:
Olenka [21]4 years ago
5 0

As the atomic radius decreases, it becomes harder to remove an electron that is closer to a more positively charged nucleus. They experience a weaker attraction to the positive charge of the nucleus. Ionization energy increases from left to right in a period and decreases from top to bottom in a group.

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Two molecules that can cross a lipid bilayer without help from membrane proteins are o2 and co2. what property allows this to oc
Dennis_Churaev [7]
Two molecules that can cross a lipid bilayer without help from membrane proteins are oxygen and carbon dioxide. The property that allows this to happen is that both oxygen and carbon dioxide molecules are nonpolar which means that they can pass easily through the hydrophobic part of the membrane. The lipid bilayer is present in all cell membranes. It consists of two layers of the fat cells which are arranged into two sheets. It functions as a barrier which marks the boundaries of the cell. The inner part of a lipid bilayer is nonpolar since it is composed of the hydrophobic end of the phospholopids. 
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3 years ago
Why is it important to keep the fractures propped open?
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3 years ago
If the equilibrium constant for the reaction A 2B C 5/2 D has a value of 4.0, what is the value of the equilibrium constant for
nirvana33 [79]

Answer:

K'=\frac{1}{16}

Explanation:

Hello!

In this case, since the given reaction is:

A+ 2B \rightleftharpoons C+ \frac{5}{2} D

Whereas the equilibrium constant is:

K=\frac{[C][D]^{5/2}}{[A][B]^2} =4.0

However, the new target reaction reverses and doubles the initial reaction to obtain:

2C+5D \rightleftharpoons 2A+4B

Whereas the equilibrium constant is:

K'=\frac{[A]^2[B]^4}{[C]^2[D]^5}

Which suggest the following relationship between the equilibrium constants:

K'=\frac{1}{K^2}

So we plug in to obtain:

K'=\frac{1}{4.0^2}\\\\K'=\frac{1}{16}

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8 0
3 years ago
Which selection contains elements that are NOT all in the same group?
Volgvan

Answer:

Iron, copper , calcium

Explanation:

Iron , copper and calcium are present in three different groups.

Iron is present in group eight.

Copper is present in group eleven.

Calcium is present in group two.

Sodium , potassium and rubidium are present in same group i.e. group one. These are alkali metals.

Fluorine, chlorine and bromine are present in group seventeen. These are halogens.

Argon, Krypton and xenon are present in same group i.e, group eighteen. All are these noble gases.

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