Question

A Top Fuel Dragster initially at rest undergoes an average acceleration of 39 m/s2 for 3.97 seconds. How far will it go in this time?

Answer 1

Answer:

s = 307.34 m

Explanation:

In order to find the distance covered by the dragster during the given time, we will use second equation of motion. The second equation of motion is written as follows:

s = Vi t + (0.5)at²

where,

s = distance covered by the dragster = ?

Vi = Initial Velocity = 0 m/s

t = time interval = 3.97 s

a = acceleration = 39 m/s²

Therefore,

s = (0 m/s)(3.97 s) + (0.5)(39 m/s²)(3.97 s)²

s = 307.34 m