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Leokris [45]
3 years ago
15

A Top Fuel Dragster initially at rest undergoes an average acceleration of 39 m/s2 for 3.97 seconds. How far will it go in this

time?
Physics
1 answer:
tigry1 [53]3 years ago
5 0

Answer:

s = 307.34 m

Explanation:

In order to find the distance covered by the dragster during the given time, we will use second equation of motion. The second equation of motion is written as follows:

s = Vi t + (0.5)at²

where,

s = distance covered by the dragster = ?

Vi = Initial Velocity = 0 m/s

t = time interval = 3.97 s

a = acceleration = 39 m/s²

Therefore,

s = (0 m/s)(3.97 s) + (0.5)(39 m/s²)(3.97 s)²

<u>s = 307.34 m</u>

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