Use ideal gas equation: pV = nRT
Now pass n to mass: n = mass / MM .... [MM is the molar mass]
pV = [mass/MM]*RT =>mass/V = [p*MM] / RT and mass / V = density
p= 130 kPa = 130,000 Pa = 130,00 joule / m^3
T = 10.0 ° + 273.15 = 283.15 k
MM of sulfur (S) = 32 g/mol = 32000 kg/mol
density = 130,000 Pa * 32000kg/mol / [8.31 joule / mol*k * 283.15 k] = 1.77*10^6 kg/m^3 = 1.77 g/L ≈ 1.8 g/L
Then, I do not get any of the option choices.
Is it possbile that the pressure is 13.0 kPa instead 130. kPa? If so the answer would be 18 g/L
Note that the mass is not used. You do not need it unless you are asked for the volume, which is not the case.
