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ElenaW [278]
3 years ago
13

Convert 1,200 meters to millimeters

Physics
1 answer:
Nikolay [14]3 years ago
6 0

Answer:

1,200,000 millimeters

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A Van de Graaff generator is charged so that the electric field at its surface is 88000 N/C . What is the magnitude of the elect
dolphi86 [110]

Answer: 1.3617×10^-14 N

Explanation: The formulae that relates electric field intensity, magnitude of charge and force is given by the formulae below.

F = Eq

Where F = electric force =?

E = strength of electric field = 88000 N/c

q = magnitude of proton charge = 1.602×10^-19 c

By substituting the parameters, we have that

F = 88000 × 1.602×10^-19

F = 13.617×10^-15

F = 1.3617×10^-14 N

4 0
3 years ago
Carbon dioxide in a piston-‐‐cylinder is expanded in a polytropic manner. The initialtemperature and pressure are 400 K and 550
Arisa [49]

Answer:

 q_poly = 14.55 KJ/kg

Explanation:

Given:

Initial State:

P_i = 550 KPa

T_i = 400 K

Final State:

T_f = 350 K

Constants:

R = 0.189 KJ/kgK

k = 1.289 = c_p / c_v

n = 1.2   (poly-tropic index)

Find:

Determine the heat transfer per kg in the process.

Solution:

-The heat transfer per kg of poly-tropic process is given by the expression:

                            q_poly = w_poly*(k - n)/(k-1)

- Evaluate w_poly:

                            w_poly = R*(T_f - T_i)/(1-n)

                            w_poly = 0.189*(350 - 400)/(1-1.2)

                            w_poly = 47.25 KJ/kg

-Hence,

                           q_poly = 47.25*(1.289 - 1.2)/(1.289-1)

                           q_poly = 14.55 KJ/kg

4 0
3 years ago
What can you calculate using the equation P equals W/t​
Natalka [10]

WE CALCULATE POWER AND RATE OF DOING WORK IS CALLED POWER

8 0
3 years ago
A particle moves in a circular path of radius 0.10 m with a constant angular speed of 5 rev/s. The acceleration of the particle
Darya [45]

Answer:

2.5 m/s²

Explanation:

Acceleration: This can be defined as the rate of change of velocity.

The S.I unit of acceleration is m/s²

For circular motion, the expression for acceleration is given as,

a = ω²r ................ Equation 1

Where a = acceleration of the particle, ω = angular speed of the particle, r = radius of the circular path.

Given: ω = 5 rev/s = 31.42 rad/s, r = 0.10 m.

Substitute into equation 1

a = 5²(0.10)

a = 25(0.10)

a = 2.5 m/s²

Hence the acceleration of the particle = 2.5 m/s²

Hence, none of the option  is correct

7 0
4 years ago
JOSEPH JOGS FROM END A TO OTHER END B OF A straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back
zzz [600]
(a) The average speed from A to B would be 1.76 metre per second and the average velocity from A to B would also be 1.76 metre per second 

<span>(b) The average speed from A to C would be 1.73 metre per second and the average velocity from A to C would be 0.87 metre per second</span>
3 0
3 years ago
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