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2 years ago

What the motion of an object that has an acceleration of 0 m/s

Physics

1 answer:

Degger [83]2 years ago

8 0

<span>Everything in the system is stable and therefore the objects motion is stable. That is to say it is not changing what it is already doing. As far as i know zero times zero is still zero. In that case then the motion must be constant or stable.</span>

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If you weigh 400 N on the Earth, what would you weigh on the moon?

Alchen [17]

Answer:

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Explanation:

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3 years ago

Two blocks on a frictionless horizontal surface are on a collision course. one block with mass 0.6 kg moves at 0.8 m/s to the ri

Elanso [62]

First we can say that since there is no external force on this system so momentum is always conserved.

$m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}$

$0.6*0.8 + 1.2*0 = 0.6*v_{1f} + 1.2*v_{2f}$

$0.48= 0.6*v_{1f} + 1.2*v_{2f}$

$0.8 = v_{1f} + 2v_{2f}$

now by the condition of elastic collision

$v_{2f} - v_{1f} = 0.8 - 0[\tex]now add two equations[tex]3*v_{2f} = 1.6$

$v_{2f} = 0.533 m/s$

also from above equation we have

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So ball of mass 0.6 kg will rebound back with speed 0.267 m/s and ball of mass 1.2 kg will go forwards with speed 0.533 m/s.

8 0

3 years ago

A turntable reaches an angular speed of "45 rev/min" in "4.10 s" after being turned on. What is its angular acceleration?

Marina86 [1]

Answer:

1.15 rad/s²

Explanation:

given,

angular speed of turntable = 45 rpm

= $45\times \dfrac{2\pi}{60}$

= $4.71\ rad/s$

time, t = 4.10 s

initial angular speed = 0 rad/s

angular acceleration.

$\alpha = \dfrac{\omega_f-\omega_0}{t}$

$\alpha = \dfrac{4.71-0}{4.10}$

$\alpha = 1.15\ rad/s^2$

Hence, the angular acceleration of the turntable is 1.15 rad/s²

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3 years ago

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Answer:

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2 years ago

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Lana71 [14]

Answer:

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