Answer:
h (3) = 0
Explanation:
In this exercise they give us the expression that governs the movement
h (t) = 5 sin (2πt)
remember that the angles are in radians.
To calculate the instantaneous velocity we substitute
h (3) = 5 sin (2π 3)
h (3) = 0
therefore the body this is its position of equilibrium
Answer:
Explanation:
a )
change in the gravitational potential energy of the bear-Earth system during the slide = mgh
= 45 x 9.8 x 11
= 4851 J
b )
kinetic energy of bear just before hitting the ground
= 1/2 m v²
= .5 x 45 x 5.8²
= 756.9 J
c ) If the average frictional force that acts on the sliding bear be F
negative work done by friction
= F x 11 J
then ,
4851 J - F x 11 = 756.9 J
F x 11 = 4851 J - 756.9 J
= 4094.1 J
F = 4094.1 / 11
= 372.2 N
Regardless of what direction an object is moving, the acceleration
due to gravity is always directed toward the center of the Earth.
That's the direction commonly known as "down".
Answer:
Explanation:
Let the slit width be a , slit separation be d and screen distance be D . Let the wavelength of light used be λ .
For diffraction through single slit
position of first minima from central fringe
x = λ (D / a)
For interference pattern
position of 5 th maxima from central fringe
x = 5 λ (D / d )
Since these positions are equal
λ (D / a) = 5 λ (D / d )
5 a = d
a / d = 1 / 5 = . 2