Two blocks of masses 3 kg and 5 kg approach each other with initial velocities 4 m/s and -6 m/s respectively. The two blocks col
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Total distance moved by bead is 1.952 cm.
Explanation:
Let first consider all data that are given in question.
1. F = 8 N ...force acting on string
2. f = 2 Hz ...frequency of system
3. β = 4 cm = 0.04 m ...wavelength of wave formed due to vibration 4. A = 1 cm = 0.01 m ...Amplitude of vibration
Under certain conditions, waves can bounce back and forth through a particular region, effectively becoming stationary. These are called standing waves.
Here,it is due to vibration induced in spring due to tension induced in string
Standing wave equation is given by
...(1)
Let first find, value of K, x, w, t
k = 2 * pi / beta ....(2)
Where β is wavelength in meters
K is wave number
k = 2 * pi / 0.01
k = 628.31
now, let us find value of w
W = 2 x pi x f ....(3)
where f is frequency in hertz
W = 2 x pi x 2
W = 4 x pi
W = 0.08
now, let us find value of v that is wave speed
Notice that some x-positions of the resultant wave are always zero no matter what the phase relationship is. These positions are called nodes.
Finding the positions where the sine function equals zero provides the positions of the nodes.
In our case, and
K * x = pi
x = 0.04 / 2
x = 0.02
Y = 1.952 cm
Finally, when bead is at middle of the string, total distance after stretch covered is 1.952 cm.