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Vlad [161]
2 years ago
6

Two blocks of masses 3 kg and 5 kg approach each other with initial velocities 4 m/s and -6 m/s respectively. The two blocks col

lide in a totally inelastic collision. What is their common final velocity after the inelastic collision?​
Physics
1 answer:
Kipish [7]2 years ago
6 0

Answer:

Explanation:

After the collision velocity of the particle is (4î - 3ĵ)m/s . ... A particle of mass 1 kg moving with a velocity of (4i^−3j^​)m/s collides with a fixed surface. ... Perfectly inelastic. D ... The common velocity of the blocks after collision is: ... A ball falls from a height of 5 m and strikes the roof of a lift. ... Stay upto date with our Newsletter! i know this is not right but just here for points see ya loser

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A pair of 10μF capacitors in a high-power laser are charged to 1.7 kV.
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Answer:

a. 17 μC b. 14.45 J

Explanation:

Here is the complete question

A pair of 10μF capacitors in a high-power laser are charged to 1.7 kV.

a. What charge is stored in each capacitor?

b. How much energy is stored in each capacitor?

a. The charge Q stored in a capacitor is Q = CV where C = capacitance  and V = voltage. Here, C = 10μF = 10 × 10⁻⁶ F and V = 1.7 kV = 1.7 × 10³ V.

So, Q = CV = 10 × 10⁻⁶ × 1.7 × 10³ = 1.7 × 10⁻² C = 17 × 10⁻³ C = 17 μC

b. The energy stored in a capacitor is given by W = 1/2CV² = 1/2 × 10 × 10⁻⁶ F × (1.7 × 10³ V)² =  1/2 × 10 × 10⁻⁶ F × 2.89 × 10⁶ V² = 1/2 × 10 × 2.89 × 10⁶ × 10⁻⁶ J = 14.45 J

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A because they are the tightest 
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