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Tpy6a [65]
2 years ago
8

At a pressure of 505 kPa, the volume of a gas is 12.00 mL. Assuming the temperature remains constant,

Chemistry
1 answer:
Sergio [31]2 years ago
8 0

Answer:

757.5 kPa

Explanation:

Boyle's law states that p1 * v1 = p2 * v2

v1 = 12 mL

v2 = 8 mL

p1 = 505 kPA

p2 = ?

(505)(12) = (p2)(8)

6060 = (p2)(8)

p2 = 757.5

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A mixture of He He , N 2 N2 , and Ar Ar has a pressure of 24.1 24.1 atm at 28.0 28.0 °C. If the partial pressure of He He is 301
Karo-lina-s [1.5K]

Answer:

16.5 atm

Explanation:

<em>A mixture of He, N₂, and Ar has a pressure of 24.1 atm at 28.0 °C. If the partial pressure of He is 3013 torr and that of Ar is 2737 mm Hg, what is the partial pressure of N₂?</em>

The total pressure of a gaseous mixture is equal to the sum of the partial pressures.

P = pHe + pN₂ + pAr

pN₂ = P - pHe - pAr [1]

We need to express pHe and pAr in atm.

pHe=3013torr.\frac{1atm}{760torr} =3.96atm

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From [1],

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8 0
3 years ago
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Lelechka [254]

Answer:

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6 0
2 years ago
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asambeis [7]

Answer:

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Explanation:

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E = 100 kg × (3×10⁸ m/s)²

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So, the required energy is 3 × 10¹⁰ J.

6 0
3 years ago
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3 years ago
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4 0
3 years ago
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