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AlladinOne [14]
4 years ago
9

How do evaporation and condensation relate to heat

Chemistry
2 answers:
bulgar [2K]4 years ago
8 0
Evaporation and Condensation is related to heat because both of them are caused by heat.
ale4655 [162]4 years ago
7 0
<span>Evaporation and condensation is caused by heat. That is how they are related. Heat causes the liquid to evaporate and float into the atmosphere which causes the formation of clouds.

Hope this helped. Have a great day!</span>
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What are the parts of this water wheel system?Label the water wheel to show the matter and forms of energy that flow through the
Setler79 [48]

Answer:

Water, wheel and paddles or bucket are the parts and mechanical energy is produced.

Explanation:

The parts of water wheel system are water, wheel and paddles or bucket. The main purpose of water wheel system is to generate useful energy by using the flowing or falling of water on the wheel. We use this water wheel system for the conversion of kinetic energy into mechanical energy such as water mill or hydroelectric plant in which the blades movement is responsible for the generation of electricity.

6 0
3 years ago
Name the parts of an electromagnet
Oxana [17]

Answer:

The iron core, copper wire, and an electricity source.

Explanation: Me

7 0
3 years ago
What is DNA fingerprinting?<br> FORENSICS
Zinaida [17]

Answer:

<em>It is a method used to identify a suspect.</em>

Explanation:

<em>DNA fingerprinting is a method used to identify an individual from a sample of DNA by looking at unique patterns in their DNA.</em>

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4 0
3 years ago
At 25 ∘ C , the equilibrium partial pressures for the reaction 3 A ( g ) + 4 B ( g ) − ⇀ ↽ − 2 C ( g ) + 3 D ( g ) were found to
VMariaS [17]

<u>Answer:</u> The standard Gibbs free energy of the given reaction is 6.84 kJ

<u>Explanation:</u>

For the given chemical equation:

3A(g)+4B(g)\rightleftharpoons 2C(g)+3D(g)

The expression of K_p for above equation follows:

K_p=\frac{(p_C)^2\times (p_D)^3}{(p_A)^3\times (p_B)^4}

We are given:

(p_A)_{eq}=5.70atm\\(p_B)_{eq}=4.00atm\\(p_C)_{eq}=4.22atm\\(p_D)_{eq}=5.52atm

Putting values in above expression, we get:

K_p=\frac{(4.22)^2\times (5.52)^3}{(5.70)^3\times (4.00)^4}\\\\K_p=0.0632

To calculate the equilibrium constant (at 25°C) for given value of Gibbs free energy, we use the relation:

\Delta G^o=-RT\ln K_{eq}

where,

\Delta G^o = standard Gibbs free energy = ?

R = Gas constant = 8.314 J/K mol

T = temperature = 25^oC=[273+25]K=298K

K_{eq} = equilibrium constant at 25°C = 0.0632

Putting values in above equation, we get:

\Delta G^o=-(8.314J/Kmol)\times 298K\times \ln (0.0632)\\\\\Delta G^o=6841.7J=6.84kJ

Hence, the standard Gibbs free energy of the given reaction is 6.84 kJ

6 0
4 years ago
Fluorine-18 is a radioactive isotope that decays by positron emission to form oxygen-18 with a half-life of 109.8 min. (A positr
Lera25 [3.4K]

Answer:

k = 6.31 x 10⁻³ min⁻¹

Explanation:

The equation required to solve this question is:

k = 0693 / t half-life

This equation is derived from the the equation from the radioctive first order reactions:

ln At/A₀ = -kt

where At is the number of isoopes after a time t , and A₀ is the number of of isotopes initially. The half-life is when the number of  isotopes has decayed by a half, so

ln(1/2) = -kt half-life

-0.693 = - k t half-life

t half-life = 109.8 min

⇒ k = 0.693 / t half-life = 0.693 / 109.8 min = 6.31 x 10⁻³ min⁻¹

6 0
3 years ago
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