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kakasveta [241]

3 years ago

8

Is the night sky divided into contellations?Is a light-Year is a measurement of time?

1 answer:

inessss [21]3 years ago

5 0

-Yes, it's divided into 88 consellations.

-Yes, it's a unit of astronomical distance equivalent to the distance that light travels in one year

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Is there a phobia for chemical reactions specifically?

gizmo_the_mogwai [7]

Answer:

chemonoia

Explanation:

Many people have a strong fear of “chemicals” that belies the evidence. It's called chemonoia – and it may be damaging their health. If you were paranoid, you might think there really was something in the water that's damaged our sense of reason.

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2 years ago

A sample of helium gas is in a sealed rigid container. What occurs as the temperature of the sample is increased

hammer [34]

The electrons will move more rapidly resulting in a higher pressure even at a consistent volume

3 0

3 years ago

Color is not very helpful in mineral identification because _____.

zhannawk [14.2K]

Some minerals tend to look alike.

8 0

3 years ago

Read 2 more answers

A cylindrical piece of metal is 4.5 dm in height with radius of 5.50 x 10^-5 km.

adell [148]

Answer:

a) $V=4.3x10^3mL$

b) $V=4.3x10^6mm^3$

c) $\rho=1.5x10^5g/L$

Explanation:

Hello,

a) In this case, the given height in cm is:

$h=4.5dm*\frac{1m}{10dm}* \frac{100cm}{1m}=45cm$

And the radius in cm is:

$r=5.50x10^{-5}km*\frac{1000m}{1km}*\frac{100cm}{1m}=5.5cm$

Thus, the volume in cubic centimeters which is also equal in mL (1cm³=mL) is:

$V=\pi (5.5cm)^2*45cm\\\\V=4.3x10^3cm^3=4.3x10^3mL$

b) In this case, the given height in mm is:

$h=4.5dm*\frac{1m}{10dm}* \frac{1000mm}{1m}=450mm$

And the radius in mm is:

$r=5.50x10^{-5}km*\frac{1000m}{1km}*\frac{1000mm}{1m}=55mm$

Thus, the volume in cubic millimeters is:

$V=\pi (55mm)^2*450mm\\\\V=4.3x10^6mm^3$

c) Finally, since 1000 mL equal 1 L, the required density in g/L turns out:

$\rho=\frac{m}{V}=\frac{6.54x10^5g}{4.3x10^3mL}*\frac{1000mL}{1L}\\ \\\rho=1.5x10^5g/L$

Best regards.

8 0

3 years ago

The air in a 2 L balloon at 0.998 atm and 34.0 °C. What will be its pressure if it is brought to a higher altitude where it now

Phantasy [73]

Answer: 0.529 atm

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 0.998 atm

$P_2$ = final pressure of gas = ?

$V_1$ = initial volume of gas = 2 L

$V_2$ = final volume of gas = 3.5 L

$T_1$ = initial temperature of gas = $34.0^oC=273+34.0=307.0K$

$T_2$ = final temperature of gas = $12.0^oC=273+12.0=285.0K$

Now put all the given values in the above equation, we get:

$\frac{0.998\times 2}{307.0K}=\frac{P_2\times 3.5}{285.0K}$

$P_2=0.529atm$

Thus the pressure if it is brought to a higher altitude where it now occupies 3.5 L and is at 12.0 °C is 0.529 atm

4 0

3 years ago