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snow_lady [41]
4 years ago
5

Which element is likely to have the highest thermal conductivity?

Chemistry
1 answer:
shepuryov [24]4 years ago
4 0
Antimony,carbon sodium gallium
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The number of particles in one mole of a chemical substances is 602,200,000,000,000,000,000,000 particles. What is the correct w
crimeas [40]

The correct way to write this number in scientific notation : 6.022 x 10²³

<h3>Further explanation </h3>

Scientific Notation is a standard form of writing numbers used in mathematical operations

The rules:

1. Writing order : first digit, decimal point, next digit

2. Then followed by powers of 10 (the value can be +/-)

If the value is> 10 (the power of 10 is +), the decimal point is moved to the left, to the right of the first digit

If the value is <10 ((the power of 10 is -), the decimal point is moved to the right, to the right of the first digit

I certainly didn't count the details of the number of zeros listed, but only saw the answer choices.

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Why should atom or ions join together to form compounds? ​
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i hope this help a little

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3 years ago
The concentration of Pb²⁺ in a sample of wastewater is to be determined by using gravimetric analysis. To a 100.0-mL sample of t
svetoff [14.1K]

Answer:

0.005404 M

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Pb^{2+}(aq) + Na_{2}CO_{3}(aq) ---> PbCO_{3}(s) + 2Na^{+}(aq)

Since you added an excess of sodium carbonate you warrantied that all the Pb^{+2} in the sample reacted with it. So we can say that the insoluble lead (II) carbonate PbCO_{3} contains all the Pb^{+2} ions in the original sample.  

The moles of PbCO_{3} are:

moles-of-PbCO_{3}=\frac{mass-of-PbCO_{3}}{Molecular-weight-of- PbCO_{3}}=\frac{0.1443g}{267\frac{g}{mol}}=0.00054 mol

One mol of Pb^{+2} is required to form one mol of PbCO_{3}. So, the stoichiometric relationship between them is 1:1.

Pb^{+2} +CO_{3}^{-2} - - - > PbCO_{3}

Knowing this, 0.00054 is also the number of moles of Pb^{+2} in the original sample.  

So, the concentration of Pb^{+2} in the original sample is:

M = \frac{mol-of-Pb^{+2}}{volume-wastewater-(liters)}=\frac{0.00054}{0.1L}=0.005404 M

8 0
4 years ago
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