What is the x-intercept of the following equation?

Six subtracted from x is less than 25

AnnZ [28]

Answer is going to be x>-19

4 0

3 years ago

Write the equation of the line that passes through the points (2,0) and (1,-2)

Darya [45]

Answer:

y

=

2

x

−

1

Explanation:

First, we need to determine the slope of the line. The formula for determining the slope of a line is:

m

=

y

2

−

y

1

x

2

−

x

1

where

m

is the slope and the x and y terms are for the points:

(

x

1

,

y

1

)

and

(

x

2

,

y

2

)

For this problem the slope is:

m

=

3

−

1

2

−

0

m

=

3

+

1

2

m

=

4

2

m

=

2

Now, selecting one of the points we can use the point slope formula to find the equation.

The point slope formula is:

y

−

y

1

=

m

(

x

−

x

1

)

Substituting one of our points gives:

y

−

1

=

2

(

x

−

0

)

y

+

1

=

2

x

Solving for

y

to put this in standard form gives:

y

+

1

−

1

=

2

x

−

1

y

+

0

=

2

x

−

1

y

=

2

x

−

1

Answer linky

=

2

x

−

1

Explanation:

First, we need to determine the slope of the line. The formula for determining the slope of a line is:

m

=

y

2

−

y

1

x

2

−

x

1

where

m

is the slope and the x and y terms are for the points:

(

x

1

,

y

1

)

and

(

x

2

,

y

2

)

For this problem the slope is:

m

=

3

−

1

2

−

0

m

=

3

+

1

2

m

=

4

2

m

=

2

Now, selecting one of the points we can use the point slope formula to find the equation.

The point slope formula is:

y

−

y

1

=

m

(

x

−

x

1

)

Substituting one of our points gives:

y

−

1

=

2

(

x

−

0

)

y

+

1

=

2

x

Solving for

y

to put this in standard form gives:

y

+

1

−

1

=

2

x

−

1

y

+

0

=

2

x

−

1

y

=

2

x

−

1

Answer link

4 0

2 years ago

the axis of symmetry of a quadratic equation is x = –3. if one of the zeroes of the equation is 4, what is the other zero?

FinnZ [79.3K]

ANSWER

The other zero is

$x = - 10$

EXPLANATION

The axis of symmetry serves as the midpoint of the two zeroes.

We were given that the axis of symmetry of the quadratic equation is
$x = - 3$

We were also given that, one of the zeroes of the quadratic equation is
$x = 4$

Let the other zero of the quadratic equation be
$x = p$

,then, we apply the midpoint formula to find the value of
$p$

Since it is the x-values of the intercepts that gives the solution, we use only the x-value part of the midpoint formula which is given by,

$\frac{x_1 + x_2}{2} = axis \: of \: symmetry$

We substitute to obtain,

$\frac{p + 4}{2} = - 3$

We multiply through by 2 to get,

$p + 4 = - 6$

This implies that,

$p = - 6 - 4$

$p = - 10$

3 0

3 years ago

Read 2 more answers

Across which axis was point E reflected?

dsp73

Answer:

X- axis

Hope that helps! :D

6 0

3 years ago

How many extraneous solutions does the equation below have?

aev [14]

Answer:

A solution is said to be extraneous, if it is a zero of the equation, but it does not satisfy the equation,when substituted in the original equation,L.H.S≠R.H.S.

The given equation consisting of variable , m is

$\frac{2 m}{2 m+3} -\frac{2 m}{2 m-3}=1\\\\ 2 m[\frac{1}{2 m+3} -\frac{1}{2 m-3}]=1\\\\ 2 m\times \frac{[2 m-3 -2 m- 3]}{4m^2-9}=1\\\\ -6 \times 2 m=4 m^2 -9\\\\ 4 m^2 +1 2 m -9=0\\\\m=\frac{-12 \pm\sqrt{12^2-4 \times 4 \times (-9)}}{2\times 4}\\\\m=\frac{-12 \pm \sqrt {144+144}}{8}\\\\m=\frac{-12 \pm \sqrt {288}}{8}\\\\m=\frac{-12 \pm 12 \sqrt{2}}{8}\\\\m=\frac{3}{2}\times(-1 \pm \sqrt{2})$

None of the two solution

$m=\frac{3}{2}\times(-1 +\sqrt{2}) and , m=\frac{3}{2}\times(-1 -\sqrt{2})$ , is extraneous.

Here, L.H.S= R.H.S

Option A: 0→ extraneous

8 0

3 years ago

Read 2 more answers