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Tanzania [10]
2 years ago
14

How do computers play a role in meteorology? Select three options.

Chemistry
2 answers:
sergij07 [2.7K]2 years ago
6 0

Answer:

It is the first 3

Explanation:

Sauron [17]2 years ago
6 0

Answer:

a b c :]

Explanation:

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State the method you will use to separate the following substances. (a) calcium carbonate from table salt (b) iodine from sodium
Vikentia [17]

Answer:

<h2>https://www.meritnation.com :)</h2>

I HOPE IT'S HELP

5 0
2 years ago
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Signs of a chemical change
dezoksy [38]

Answer: There are five signs of chemical change

  • Color Change
  • Production of an odor
  • Change of Temperature
  • Evolution of Gas (bubbles start to form)
  • Precipitate (starts to form a solid)

When these signs start to form you know chemical change is at work.

Hope this helps :)

5 0
3 years ago
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A 0.15 M NaOH solution has a volume of 0.125 L but is then diluted to 0.15 L. What is the concentration of the new solution
tresset_1 [31]

Answer:

.125 M

Explanation:

.15 M/L   * .125 L = .01875 moles

now dilute to 150 cc  (by adding 25 cc)

.01875M / (150/1000) = .125M

5 0
2 years ago
One hundred grams of water is saturated with NH CI at
Pepsi [2]

Answer:

  • About 18 g of NH₄Cl will precipitate.

Explanation:

The <em>table G</em> is the graph of the solubility curves for several solutes which is attached.

The second picture identifies the solubilities for the  NH₄Cl at 50ºC and 10ºC.

The solubility of NH₄Cl at 50ºC is about 52 g/ 100 g of water.

The solubility of NH₄Cl at 10ºC is about 34 g / 100 g of water.

Then, at 50ºC 100 g of water saturated with NH₄Cl contains about 52 g of NH₄Cl and 100 g of water saturated with NH₄Cl contains 34 g of NH₄Cl.

The difference, 52g - 34 g of NH₄Cl shall precipitate:

          52 g - 34 g = 18g ← answer

7 0
3 years ago
Consider the following balanced equation:3Ca(NO3)2(aq) + 2Na3PO4(aq) → Ca3(PO4)2(s) + 6NaNO3(aq)If 24.2 moles of Na3PO4(aq) reac
Tomtit [17]

Answer:

69.7% is percent yield

Explanation:

Based on the reaction:

3Ca(NO3)2(aq) + 2Na3PO4(aq) → Ca3(PO4)2(s) + 6NaNO3(aq)

2 moles of Na3PO4 react producing 6 moles of NaNO3.

As 24.2 moles of Na3PO4 react, theoretical moles of NaNO3 produced are:

24.2 moles Na3PO4 * (6 moles NaNO3 / 2 moles Na3PO4) =

72.6 moles of NaNO3

As there are produced 50.6 moles of NaNO3, percent yield is:

50.6 moles NaNO3 / 72.6 moles NaNO3 =

<h3>69.7% is percent yield</h3>
7 0
2 years ago
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