1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tanzania [10]
2 years ago
14

How do computers play a role in meteorology? Select three options.

Chemistry
2 answers:
sergij07 [2.7K]2 years ago
6 0

Answer:

It is the first 3

Explanation:

Sauron [17]2 years ago
6 0

Answer:

a b c :]

Explanation:

You might be interested in
Most gases exist as molecules, for example, fluorine is F2.
Kryger [21]
They are all stable and have eight valence electrons
4 0
2 years ago
Read 2 more answers
A 35.0 ml sample of 0.225 m hbr was titrated with 42.3 ml of koh. What is the concentration of the koh?
Lemur [1.5K]

Answer:

The concentration of KOH is 0.186 M

Explanation:

First things first, we need too write out the balanced equation between HBr and KOH.

This is given as;

KOH (aq) + HBr (aq) → KBr (aq) + H2O (l)

From the reaction above, we can tell that it takes 1 mole of KOH to react with 1 mole of HBr.

We use the acid base formular in calculating unknown concentrations. This is given as;

\frac{CaVa}{CbVb}  = \frac{na}{nb}

where;

Ca = Concentration of acid

Va = Volume of acid

Cb = Concentration of base

Vb = Volume of base

na = Number of moles of acid

nb = Number of moles of base

KOH is the base and HBr is acid.

Hence;

Ca = 0.225

Va = 35

Cb = ?

Vb = 42.3

na = 1

nb = 1

Making Cb subject of formular we have;

Cb = \frac{CaVaNb}{VbNa}

Cb = (0.225 * 35 * 1) / (42.3 * 1)

Cb = 0.186 M

5 0
3 years ago
Find the density of metal with a volume 4.0 cm and a mass of 8.0 grams.
olga_2 [115]
D=m/v

so,

d=8.0g/4.0cm

d=2

3 0
2 years ago
Type the correct answer in the box. Express your answer to three significant figures. This balanced equation shows the reaction
Ratling [72]

Answer:

514.5 g.

Explanation:

  • The balanced equation of the reaction is: 2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O.
  • It is clear that every 2.0 moles of NaOH react with 1.0 mole of H₂SO₄ to produce 1.0 mole of Na₂SO₄ and 2.0 moles of 2H₂O.
  • Since NaOH is in excess, so H₂SO₄  is the limiting reactant.
  • We need to calculate the no. of moles of 355.0 g of H₂SO₄:

n of H₂SO₄ = mass/molar mass = (355.0 g)/(98.0 g/mol) = 3.622 mol.

Using cross multiplication:

∵ 1.0 mol H₂SO₄ produces → 1.0 mol of Na₂SO₄.

∴ 3.622 mol H₂SO₄ produces → 3.662 mol of Na₂SO₄.

  • Now, we can get the theoretical mass of Na₂SO₄:

∴ mass of Na₂SO₄ =  no. of moles x molar mass = (3.662 mol)(142.04 g/mol) = 514.5 g.

8 0
2 years ago
A runner stood at the 100-meter mark on a track. When the timer started, the runner sprinted north to the 200-meter mark. It too
Olegator [25]

Answer:

8 m/s north

Explanation:

3 0
3 years ago
Read 2 more answers
Other questions:
  • An anode is an electrode immersed in the half-cell where _____ takes place.
    5·2 answers
  • Which of the following is not a benefit of the water cycle?
    10·2 answers
  • Suppose your thermometer is off by 1.5 oc i.e. it reads values that are 1.5 oc higher. how would this affect the results in this
    10·1 answer
  • A concentrated aqueous solution of Pb(NO3)2 is slowly added to 1.0 L of a mixed aqueous solution containing 0.010 M Na2CrO4 and
    10·1 answer
  • Need these ASAP ignore the use evidence from the text in question 1
    7·1 answer
  • When a chemical change occurs _____.
    7·1 answer
  • what is the molecular formula of a compound with an empirical formula of CH and a molar mass of 91.14 G/mole
    12·1 answer
  • Identify the reactants and products and write chemical equations for each of the following reactions: a. Gaseous chlorine reacts
    14·1 answer
  • What is the hydrogen ion concentration of oven cleaner?
    14·1 answer
  • What is the density of a salt solution if 75.0 ml of the solution has a mass of 32.0 g?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!