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Murrr4er [49]
3 years ago
11

2. Categorize each statement as true or false. A cylindrical capacitor is essentially a parallel-plate capacitor rolled into a t

ube.The dielectric constant indicates the distance by which the two plates of a capacitor are separated.The charge on a capacitor increases quickly at first, then much more slowly as the capacitor charges.The voltage across a capacitor in an RC circuit increases linearly during charging.One of the principle purposes of a capacitor is to store electric potential energy.A capacitor charges rapidly when connected to an RC circuit with a battery. True False
Physics
1 answer:
Kruka [31]3 years ago
6 0

Answer:

Explanation:

False --> A cylindrical capacitor is essentially a parallel plate capacitor rolled into a tube. This is because a cylindrical capacitor comprises two cylinders.

False --> The dielectric constant indicates the distance by which the two plates of a capacitor are separated.

True --> The charge on a capacitor increases quickly at first, then much more slowly as the capacitor charges. This is because the charge on the capacitor increases exponentially.

False --> The voltage across a capacitor in an RC circuit increases linearly during charging. This is because the voltage increases exponentially.

True --> One of the principal purposes of a capacitor is to store electric potential energy.

True --> A capacitor charges rapidly when connected to an RC circuit with a battery. This is because a cylindrical capacitor is basically a parallel plate capacitor rolled into a tube.

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A cat’s crinkle ball toy of mass 15g is thrown straight up with an initial speed of 3m/s . Assume in this problem that air drag
Readme [11.4K]

Answer:

(a)0.0675  J

(b)0.0675 J

(c)0.0675 J

(d)0.0675 J

(e)-0.0675 J

(f)0.459 m

Explanation:

15g = 0.015 kg

(a) Kinetic energy as it leaves the hand

E_k = \frac{mv^2}{2} = \frac{0.015*3^2}{2} = 0.0675  J

(b) By the law of energy conservation, the work done by gravitational energy as it rises to its peak is the same as the kinetic energy as the ball leave the hand, which is 0.0675 J

(c) The change in potential energy would also be the same as 0.0675J in accordance with conservation law of energy.

(d) The gravitational energy at peak point would also be the same as 0.0675J

(e) In this case as the reference point is reversed, we would have to negate the original potential energy. So the potential energy as the ball leaves hand is -0.0675J

(f) Since at the maximum height the ball has potential energy of 0.0675J. This means:

mgh = 0.0675

0.015*9.81h = 0.0675

h = 0.459 m

The ball would reach a maximum height of 0.459 m

4 0
3 years ago
An ideal spring hangs from the ceiling. A 2.15 kg mass is hung from the spring, stretching the spring a distance d = 0.0895 m fr
Igoryamba

Answer:

The kinetic energy of the mass at the instant it passes back through the equilibrium position is 0.06500 J.

Explanation:

Given that,

Mass = 2.15 kg

Distance = 0.0895 m

Amplitude = 0.0235 m

We need to calculate the spring constant

Using newton's second law

F= mg

Where, f = restoring force

kx=mg

k=\dfrac{mg}{x}

Put the value into the formula

k=\dfrac{2.15\times9.8}{0.0895}

k=235.41\ N/m

We need to calculate the kinetic energy of the mass

Using formula of kinetic energy

K.E=\dfrac{1}{2}mv^2

Here, v = A\omega

K.E=\dfrac{1}{2}m\times(A\omega)^2

Here, \omega=\sqrt{\dfrac{k}{m}}^2

K.E=\dfrac{1}{2}m\times A^2\sqrt{\dfrac{k}{m}}^2

K.E=\dfrac{1}{2}kA^2

Put the value into the formula

K.E=\dfrac{1}{2}\times235.41\times(0.0235)^2

K.E=0.06500\ J

Hence, The kinetic energy of the mass at the instant it passes back through the equilibrium position is 0.06500 J.

8 0
3 years ago
Select all that apply. Which of the following are characteristics of acids? contain hydroxide ion or produce it in a solution ta
julia-pushkina [17]
These are the characteristics that apply:

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3 years ago
What is the angle of reflection?
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<span>The angle of reflection is C). the angle that the reflected ray makes with a line drawn perpendicular to the reflecting surface, that way the reflection can be seen.

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8 0
3 years ago
Read 2 more answers
Show the weight of the ladder and draw the missing Frictional force.
madreJ [45]
Since there is no friction between the ladder and the wall, there can be no vertical force component. That's the tricky part ;)

So to find the weight, divide the 100N <em>normal</em> force by earths gravitational acceleration, 9.8m/s^2

W =  \frac{N}{g}  =  \frac{100N}{9.8m/s^{2}} =  \frac{100}{9.8} = 10.2kg


Then;
Draw an arrow at the base of the ladder pointing towards the wall with a value of 30N, to show the frictional force.
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3 years ago
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