The average speed of the bus from Lansing to Detroit is
![v_1 = 104.5 km/h](https://tex.z-dn.net/?f=v_1%20%3D%20104.5%20km%2Fh)
while the average speed of the bus from Detroit to Lansing is
![v_2 =56.2 km/h](https://tex.z-dn.net/?f=v_2%20%3D56.2%20km%2Fh)
The distance covered by the bus in the two trips is the same (the distance between the two cities), therefore, the average speed of the round trip can be calculated as the mean of the two speeds:
Answer:16.096
Explanation:
Given
mass of dog![\left ( m_d\right )=10kg](https://tex.z-dn.net/?f=%5Cleft%20%28%20m_d%5Cright%20%29%3D10kg)
mass of boat![\left ( m_b\right )=46kg](https://tex.z-dn.net/?f=%5Cleft%20%28%20m_b%5Cright%20%29%3D46kg)
distance moved by dog relative to ground=![x_d](https://tex.z-dn.net/?f=x_d)
distance moved by boat relative to ground=![x_b](https://tex.z-dn.net/?f=x_b)
Distance moved by dog relative to boat=7.8m
There no net force on the system therefore centre of mass of system remains at its position
0=![m_d\times x_d+m_b\dot x_b](https://tex.z-dn.net/?f=m_d%5Ctimes%20x_d%2Bm_b%5Cdot%20x_b)
0=![10\times x_d+46\dot x_b](https://tex.z-dn.net/?f=10%5Ctimes%20x_d%2B46%5Cdot%20x_b)
![x_d=-4.6x_b](https://tex.z-dn.net/?f=x_d%3D-4.6x_b)
i.e. boat will move opposite to the direction of dog
Now
![|x_d|+|x_b|=7.8](https://tex.z-dn.net/?f=%7Cx_d%7C%2B%7Cx_b%7C%3D7.8)
substituting
value
![5.6|x_b|=7.8](https://tex.z-dn.net/?f=5.6%7Cx_b%7C%3D7.8)
![|x_b|=1.392m](https://tex.z-dn.net/?f=%7Cx_b%7C%3D1.392m)
![|x_d|=6.4032m](https://tex.z-dn.net/?f=%7Cx_d%7C%3D6.4032m)
now the dog is 22.5-6.403=16.096m from shore
The Sun is a star around which our planet Earth and other planets and satellites of our solar system revolve along specific orbits. Sun appears to be spherical in shape and consists of glowing hot gases. It contains mostly hydrogen and helium gases. The temperature of the gas mixture is extremely high.
Therefore, the Sun mostly composed of hydrogen and helium gases.
(Answer) B. Composition mostly hydrogen and helium gas, Mass 1.989 x 10^30 Kg
So the velocity of ball b is 6.50kg then just simple reciprocate the kgm of ball A
Answer:
489.19m
Explanation:
To find the minimum distance you first calculate the time in which the teacher stops:
![v=v_o-at\\\\t=\frac{v_o-v}{a}=\frac{34.5m/s-0m/s}{2.5m/s^2}=13.8s](https://tex.z-dn.net/?f=v%3Dv_o-at%5C%5C%5C%5Ct%3D%5Cfrac%7Bv_o-v%7D%7Ba%7D%3D%5Cfrac%7B34.5m%2Fs-0m%2Fs%7D%7B2.5m%2Fs%5E2%7D%3D13.8s)
however, the reaction of the teacher is 0.31s later, then you use
t=13.8-0.31s=13.49s
during this time the camper has traveled a distance of:
(1)
Next you calculate the distance that teacher has traveled for 13.6s:
(2)
The minimum distance between the driver and the camper will be the difference between (2) and (1):
![x_{min}=692.88m-203.69m=489.19m](https://tex.z-dn.net/?f=x_%7Bmin%7D%3D692.88m-203.69m%3D489.19m)