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mr Goodwill [35]
1 year ago
14

a hot pot of water is set on the counter to cool. after a few minutes it has lost 755 j of heat energy. how much heat energy has

the surrounding air gained?
Physics
1 answer:
velikii [3]1 year ago
5 0

The heat energy the surrounding air gained is <u>755 j.</u>

Energy is a quantitative property given to a body or physical system and can be identified as work being done in the form of heat and light. Energy is Conserved - The law of conservation of energy states that energy can be transformed into form, but cannot be created or destroyed. Energy is the ability to do work. It can exist in electrical, kinetic, thermal, electrical, chemical, nuclear, or other forms.

<u>Concept:-</u>

Since the energy is always conserved, the energy lost by the hot water is gained bt the surrounding

- energy lost  = + energy gained by the surrounding

- 755 j = + <u>755 j</u>

<u />

Energy exists in many forms. Examples include light energy, thermal energy, mechanical energy, gravitational energy, electrical energy, acoustic energy, chemical energy, and nuclear or atomic energy. Each form can be transformed or changed into other forms.

Learn more about energy here:-brainly.com/question/13881533

#SPJ1

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2) Two railway tracks are parallel to west east direction. Along one track, train A moves with a speed of 45 m/s from
OLEGan [10]

Answer:

Relative\ Velocity = 105m/s

Explanation:

Given

V_A = 45m/s

V_B = 60m/s

Required

Determine the speed of B w.r.t A

The question implies that, we determine the relative velocity of B w.r.t A

Because both trains are moving towards one another, the required velocity is a sum\ of\ velocities\ of both trains:

This is shown below:

Relative\ Velocity = V_A + V_B

Relative\ Velocity = 45m/s + 60m/s

Relative\ Velocity = 105m/s

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3 years ago
A point charge of 4.0 µC is placed at a distance of 0.10 m from a hard rubber rod with an electric field of 1.0 × 103 . What is
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The electric potential energy of the point charge is 4.

the electric potential energy of the point charge at 1.3 m is 5.2.

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3 years ago
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How long does it take a wave to travel 1200 meters with the speed of 3 X 108m/sec?
Vladimir79 [104]
Around 3.70 seconds unless traveling through media

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What would happen if there were no friction between the girl and the slope?
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She'll most likely fall
7 0
3 years ago
Long Jump: inital center of mass height of 1.08 m, final center of mass height of 0.42 m, projection velocity of 8.7 m/s, projec
sammy [17]

Answer:

1) The maximum jump height is reached at A. 0.337s

2) The maximum center of mass height off of the ground is B. 1.64m

3) The time of flight is C. 0.834s

4) The distance of jump is B. 7.49m

Explanation:

First of all we need to decompose velocity in its rectangular components, so

v_{xi}=8.7m/s(cos 22.3\°)=8.05m/s= constant\\v_{yi}=8.7m/s(sin 22.3\°)=3.3m/s

1) We use, v_{fy}=v_{iy}-gt, as we clear it for t and using the fact that v_{fy}=0 at max height, we obtain t=\frac{v_{iy}}{g} =\frac{3.3m/s}{9,8m/s^{2}} =0.337s

2) We can use the formula y_{max}=y_{i}+v_{iy}t-\frac{gt^{2}}{2} for t=0.337s, so

y_{max}=1.08m+(3.3m/s)(0.337s)-\frac{(9.8m/s^{2})(0.337)^{2}}{2}=1.64m

3) We can use the formula y_{f}=y_{i}+v_{iy}t-\frac{gt^{2}}{2}, to find total time of fligth, so 0.42=1.08+3.3t-\frac{(9.8)t^{2}}{2}\\0=-4.9t^{2}+3.3t+0.66, as it is a second-grade polynomial, we find that its positive root is t=0.834s

4) Finally, we use x=v_{x}t=8.05m/s(0.834s)=6.71m, as it has an additional displacement of 0.77m due the leg extension we obtain,

x=6.71m+0.77m=7.48m, aprox x=7.49m

5 0
4 years ago
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