1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Phoenix [80]
3 years ago
13

As speed increases, how does the potential, kinetic, and total energy levels change?

Physics
1 answer:
Anastaziya [24]3 years ago
4 0
Potential equals kenecric at the bottom so potential would also increas
You might be interested in
The four tires of an automobile are inflated to a gauge pressure of 2.2 105 Pa. Each tire has an area of 0.023 m2 in contact wit
Stels [109]

Answer:

Force, F = 20240 N

Explanation:

It is given that,

Pressure exerted by the four tires of an automobile, P=2.2\times 10^5\ Pa

Area of each tire, A=0.023\ m^2

Area of 4 tires,  A=0.092\ m^2

We know that the pressure exerted by an object is equal to the force per unit area. Its formula is given by :

P=\dfrac{F}{A}

F=P\times A

F=2.2\times 10^5\times 0.092

F = 20240 N

So, the weight of the automobile is 20240 N. Hence, this is the required solution.

7 0
4 years ago
What is the magnitude of the magnetic field at a point midway between them if the top one carries a current of 19.5 A and the bo
Phantasy [73]

Answer:

The magnetic field will be \large{\dfrac{1.4 \times 10^{-4}}{d}} T, '2d' being the distance the wires.

Explanation:

From Biot-Savart's law, the magnetic field (\large{\overrightarrow{B}}) at a distance 'r' due to a current carrying conductor carrying current 'I' is given by

\large{\overrightarrow{B} = \dfrac{\mu_{0}I}{4 \pi}} \int \dfrac{\overrightarrow{dl} \times \hat{r}}{r^{2}}}

where '\overrightarrow{dl}' is an elemental length along the direction of the current flow through the conductor.

Using this law, the magnetic field due to straight current carrying conductor having current 'I', at a distance 'd' is given by

\large{\overrightarrow{B}} = \dfrac{\mu_{0}I}{2 \pi d}

According to the figure if 'I_{t}' be the current carried by the top wire, 'I_{b}' be the current carried by the bottom wire and '2d' be the distance between them, then the direction of the magnetic field at 'P', which is midway between them, will be perpendicular towards the plane of the screen, shown by the \bigotimes symbol and that due to the bottom wire at 'P' will be perpendicular away from the plane of the screen, shown by \bigodot symbol.

Given \large{I_{t} = 19.5 A} and \large{I_{B} = 12.5 A}

Therefore, the magnetic field (\large{B_{t}}) at 'P' due to the top wire

B_{t} = \dfrac{\mu_{0}I_{t}}{2 \pi d}

and the magnetic field (\large{B_{b}}) at 'P' due to the bottom wire

B_{b} = \dfrac{\mu_{0}I_{b}}{2 \pi d}

Therefore taking the value of \mu_{0} = 4\pi \times 10^{-7} the net magnetic field (\large{B_{M}}) at the midway between the wires will be

\large{B_{M} = \dfrac{4 \pi \times 10^{-7}}{2 \pi d} (I_{t} - I_{b}) = \dfrac{2 \times 10^{-7}}{d} = \dfrac{41.4 \times 10 ^{-4}}{d}} T

5 0
3 years ago
ou are sitting in your car at rest at a traffic light with a bicyclist at rest next to you in the adjoining bicycle lane. As soo
madam [21]

Till the time car is just adjacent to the bicycle we can say

distance moved by cycle = distance moved by car

Time taken by car to accelerate from rest

t = \frac{v_f - v_i}{a}

t = \frac{49 - 0}{7} = 7 s

Time taken by cycle to accelerate

t = \frac{23 - 0}{15} = 1.53 s

now the distance moved by cycle in time "t"

d = \frac{23 + 0}{2}*1.53 + 23(t - 1.53)

distance moved by car in same time

d = \frac{7t + 0}{2}(t)

now make them equal

3.5t^2 = 17.595 - 35.19 + 23t

3.5 t^2 - 23t + 17.595 = 0

t = 5.68 s

so cycle will move ahead of car for t = 5.68 s

8 0
3 years ago
Read 2 more answers
Suppose you are working on green house, which light you would<br> use for their growth?
nikitadnepr [17]

Answer:

Fluorescent lighting is usually used.

Explanation:

6 0
3 years ago
Read 2 more answers
What is E equal to in relativity? ​
vladimir1956 [14]

\huge \underline \mathtt \colorbox{cyan}{E=mc squared}

(E=mc^2)

<h3><u>Where</u><u>:</u></h3>

<u>m</u><u> </u><u>is mass</u>

<u>And c is a constant for speed of light</u>

7 0
3 years ago
Read 2 more answers
Other questions:
  • A cleaver physics professor wants to create a situation where a block starts from rest at the top of a 31.0° inclined plane and
    13·1 answer
  • A hockey player uses her hockey stick to exert a force of 6.81 N on a stationary hockey puck. The hockey puck has a mass of 165
    6·1 answer
  • The volume of a cylinder is V space equals space pi space r squared space h, where r is the radius of the circular faces and h i
    9·1 answer
  • What is the force acting on the object?(g=10m/s^2)​
    10·1 answer
  • Please help me answer this question! Will appreciate help very much. a) Draw a circuit to show 3 lights in series b) Draw a circ
    7·1 answer
  • What happens when a light ray is parallel to the principal axis ?
    8·1 answer
  • What color of light has the shortest wavelength
    14·1 answer
  • How much force would cause a 120 kg object to decelerate from a rate of 16m/s to 13 m/s in 5 seconds
    7·1 answer
  • If you catch the ruler 4.9 cm from the lower end, what is your reaction time?
    8·1 answer
  • What is the speed of a transverse wave in a rope of length 3. 1 m and mass 86 g under a tension of 380 n?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!