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Answer:
Explanation:
The force exerted between two current-carrying wires is given by
where
is the vacuum permeability
I1 and I2 are the two currents
L is the length of the segment of wire on which we want to calculate the force
r is the distance between the wires
In this problem we have:
Substituting into the formula, we find:
And since the direction of the two currents is opposite, the force between the wires is repulsive.
To solve this problem we will apply the concepts related to electromagnetic force. This force is defined as the product between the free space permeability constant, the product of the two currents found, at the rate of the distance that separates them. In this way mathematically it can be given as,
Here,
= Permeability of free space
I = Each current
d = Distance
Replacing with our values,
Therefore the force is
We will apply the concepts related to Newton's second law. At the same time we will convert everything to the system of international units.
The values of the velocities are,
We know that the acceleration is equivalent to the change of the speed in a certain time therefore
Now applying the Newton's second law we have,
Therefore the approximate magnitude is 8516.36N