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stellarik [79]
2 years ago
7

A piece of wire 26 m long is cut into two pieces. one piece is bent into a square and the other is bent into an equilateral tria

ngle. (a) how much wire should be used for the square in order to maximize the total area? 26 m (b) how much wire should be used for the square in order to minimize the total area?
Physics
1 answer:
kiruha [24]2 years ago
8 0
<span>a) All the 26m should be used to bent into a square to maximize the total area (= 42.25 m2) b) 1.4136m should be bent into a square and the rest (= 24.586m) should be bent into an equilateral triangle to minimize the total area (= 29.0835m2)</span>
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An electron is accelerated through 1.90 103 V from rest and then enters a uniform 1.80-T magnetic field.
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https://www.slader.com/discussion/question/an-electron-is-accelerated-through-240-times-103-v-from-rest-and-then-enters-a-uniform-170-t-magnetic-field-what-are-a-the-maximum-and-b-the-9e425fbd/

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3 years ago
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GenaCL600 [577]

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8 0
2 years ago
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3 years ago
The engineer of a passenger train traveling at 25.0m/s sights a freight train whose caboose is 200m ahead on the same track. The
Vika [28.1K]

Answer:

No, there won't be a collision.

Explanation:

We will use the constant acceleration formulas to calculate,

v = u + a*t

0 = 25 + (-0.1)*t

t = 250 seconds (the time taken for the passenger train to stop)

v^2 = u^2 + 2*a*s

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s = 3125 m (distance traveled by passenger train to stop)

If the distance traveled by freight train in 250 seconds is less than (3125-200=2925 m) than the collision will occur

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Distance = (15)*(250)

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As the distance is way more, there won’t be a collision

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