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stellarik [79]
2 years ago
7

A piece of wire 26 m long is cut into two pieces. one piece is bent into a square and the other is bent into an equilateral tria

ngle. (a) how much wire should be used for the square in order to maximize the total area? 26 m (b) how much wire should be used for the square in order to minimize the total area?
Physics
1 answer:
kiruha [24]2 years ago
8 0
<span>a) All the 26m should be used to bent into a square to maximize the total area (= 42.25 m2) b) 1.4136m should be bent into a square and the rest (= 24.586m) should be bent into an equilateral triangle to minimize the total area (= 29.0835m2)</span>
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\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \alpha=\frac{\omega_f^2-\omega_i^2}{2\theta}\\\Rightarrow \alpha=\frac{0^2-1.5^2}{2\times 2\pi \times 40}\\\Rightarrow \alpha=-0.0047\ rad/s^2

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