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To make 1000. L of bleach solution 1.69×10⁴ L of Cl₂(g) at STP will be needed .
<h3>What is Balanced chemical equation?</h3>A balance chemical equation is an equation that contain same number of atoms as well as of each element on each side of reaction.
<h3>What is Density?</h3>It is ratio of mass to the volume.
Density=
Now,
The balanced chemical equation of preparing bleach from chlorine is as follow:
Cl₂(g) + 2NaOH(aq) → NaClO(aq) + NaCl(aq) + H₂O(l)
Now,
To calculate the Moles of NaClO in 1000L solution, first calculate it's mass.
Mass of NaClO = Density × Volume
= 1.07 × 1000L ×
×
= 56175g
Now, we have to calculate moles of NaClO
Hence,
Moles of NaClO =
=
= 754.63 mol
Now,
According to the reaction number of moles of Cl₂ is equal to the number of moles of NaClO.
Hence,
moles of Cl₂ = 754.63 mol
Now , in order to calculate litres of Cl₂ at STP,
We know that
1 mol Cl₂ = 22.4 L of Cl₂
754.63 mol of Cl₂ = 754.63 mol × 22.4 L
= 1.69×10⁴ L of Cl₂
Thus from the above conclusion we can say that , to make 1000. L of bleach solution 1.69×10⁴ L of Cl₂(g) at STP will be needed .
Learn more about Balanced Chemical Equation here:brainly.com/question/27135494
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