Answer: 167 g
Explanation:
1) The depression of the freezing point of a solution is a colligative property ruled by this equation:
ΔTf = i × m × Kf
Where:
ΔTf is the decrease of the freezing point of the solvent due to the presence of the solute.
i is the Van't Hoof factor and is equal to the number of ions per each mole of solute. It is only valid for ionic compounds. Here the solute is not ionice, so you take i = 1
Kf is the molal freezing constant and is different for each solvent. For water it is 1.86 m/°C
2) Calculate the molality (m) of the solution
ΔTf = i × m × Kf ⇒ m = ΔTf / ( i × Kf) = 5.00°C / 1.86°C/m = 2.69 m
3) Calculate the number of moles from the molality definition
m = moles of solute / kg of solvent ⇒ moles of solute = m × kg of solvent
moles of solute = 2.69 m × 1.00 kg = 2.69 moles
4) Convert moles to grams using the molar mass
molar mass of C₂H₆O₂ = 62.07 g/mol
mass in grams = number of moles × molar mass = 2.69 moles × 62.07 g/mol = 166.97 g ≈ 167 g
Answer:
Lithium,Sodium,Potassium all belong to transition metals
Answer:
The pressure exerted by the buggy on the surface of Mars is 1600 pascals.
Explanation:
The pressure is determined by the definition of stress, which is the force exerted by the buggy on the martian surface divided by the contact area of the latter:
Where:
- Stress, measured in pascals.
- Force, measured in newtons.
- Area, measured in square meters.
The force is the weight of the buggy (40 N) and 
, the stress is now calculated:
The pressure exerted by the buggy on the surface of Mars is 1600 pascals.
Weathered debris is a result of FROST WEDGING.
Frost wedging refers to the process by which water freeze and thaw continuously over a period of time. Rocks usually contain crevices which are filled with water. Due to the extreme temperature changes during the night and day and during the course of season changes, the water in the crevices freeze and thaw continuously leading to the cracking of the rocks as a result of the expansion and contraction of the rocks.<span />
