The balanced chemical reaction is written as:
Sb2S3 + 6HCl = 6SbCl<span>3 + 3H2S
We are given the amount of </span><span>antimony(III) sulfide to be used in the reaction. This is amount will be used for the calculations. We do as follows:
2.85 g Sb2S3 ( 1 mol / </span><span>339.715 g ) ( 6 mol SbCl3 / 1 mol Sb2S3 ) (</span> 228.13 g / mol ) = 11.48 g SbCl3
Answer:

Explanation:
![\rm MX(s) $\, \rightleftharpoons \,$ M$^{+}$(aq) + $^{-}$(aq); $K_{\text{sp}}$ = [M$^{+}$][X$^{-}$]\\\\\text{$K_{\text{sp}}$ gives us information on}\\\\\boxed{\textbf{ the equilibrium between the solid and its ions in solution}}](https://tex.z-dn.net/?f=%5Crm%20MX%28s%29%20%24%5C%2C%20%5Crightleftharpoons%20%5C%2C%24%20M%24%5E%7B%2B%7D%24%28aq%29%20%2B%20%24%5E%7B-%7D%24%28aq%29%3B%20%24K_%7B%5Ctext%7Bsp%7D%7D%24%20%3D%20%5BM%24%5E%7B%2B%7D%24%5D%5BX%24%5E%7B-%7D%24%5D%5C%5C%5C%5C%5Ctext%7B%24K_%7B%5Ctext%7Bsp%7D%7D%24%20gives%20us%20information%20on%7D%5C%5C%5C%5C%5Cboxed%7B%5Ctextbf%7B%20the%20equilibrium%20between%20the%20solid%20and%20its%20ions%20in%20solution%7D%7D)
It tells us nothing about the amount of precipitate that will form or the temperature at which the equilibrium occurs.
Answer:
Explanation:
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The mass defect for the isotope thorium-234 if given mass is 234.04360 amu is 1.85864 amu.
<h3>How do we calculate atomic mass?</h3>
Atomic mass (A) of any atom will be calculated as:
A = mass of protons + mass of neutrons
In the Thorium-234:
Number of protons = 90
Number of neutrons = 144
Mass of one proton = 1.00728 amu
Mass of one neutron = 1.00866 amu
Mass of thorium-234 = 90(1.00728) + 144(1.00866)
Mass of thorium-234 = 90.6552 + 145.24704 = 235.90224 amu
Given mass of thorium-234 = 234.04360 amu
Mass defect = 235.90224 - 234.04360 = 1.85864 amu
Hence required value is 1.85864 amu.
To know more about Atomic mass (A), visit the below link:
brainly.com/question/801533
I think the correct answer from the choices listed above is option D. The net ionic equation that will describe the reaction of the reactants when mixed is expressed as:
<span>2PO43–(aq) + 3Ca2+(aq) → Ca3(PO4)2(s)
</span>
Hope this answers the question. Have a nice day.