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Delicious77 [7]
3 years ago
8

The average daily diet of an adult woman is 2.4×103kcal. the molar mass of atp is 507 g/mole. part a if all the energy in her di

et is converted to atp, how many kg of atp are synthesized in one day?
Chemistry
1 answer:
mezya [45]3 years ago
3 0
To answer this question, we should give the standard free energy change of ATP to ADP conversion that is equal to 30.5 kJ/mol ATP. In this case, 2400 kcal is equal to 10041. 6 kJ. Hence, the mol of ATP produced is 329.23 mol ATP or equal to 166.93 kg ATP. 
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A 1 l container contains O2 gas at stp. if the diameter of the O2 molecule is 3.75 * 10^-10 m the mean free path of the o2 molec
Luba_88 [7]

The mean free path of the O₂ molecule is 5.97*10^{-5} m.

The mean free path of the O₂ molecule is calculated by the formula -

λ = \frac{1}{\sqrt{2}*\pi *d^{2}*n}

In this formula, λ represents mean free path of gas, d represents diameter and n is number of molecules.

As per the known fact, 1 mole of gas occupies 22.4 liter at STP.

So. 1 liter of O₂ gas will have number of moles = \frac{1*1}{22.4}

Number of moles = 0.045

Also, we are aware that 1 mole contains 6.02*10^{23} molecules.

So, 0.045 moles will contain number of molecules = 6.02*10^{23}*0.045

Number of molecules = 2.7*10^{22} molecules

Now, keeping the values in formula to find mean free path of gas -

λ =  \frac{1}{1.4*3.14*(3.75*10^{-10})^{2} *2.7*10^{22} }

λ = \frac{1}{16746.7}

λ = 5.97*10^{-5} m

Hence, the mean free path of the O₂ molecule is 5.97*10^{-5} m.

Learn more about calculation of mean free path -

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8 0
2 years ago
Consider two different solutions of the same UV-absorbing compound. Upon UV-analysis, Solution B gave an absorbance of 1.0 and S
Juliette [100K]

We have that the Concentration of solution B is 2.5 times more than solution A's concentration.

<h3>UV(Ultra violent) rays</h3>

Question Parameters:

Upon UV-analysis, Solution B gave an absorbance of 1.0

Solution A gave an absorbance of 0. 4

Generally the equation for the Absorbance    is mathematically given as

A = e*c*L

Therefore

For A solution  

0.4 = e*[cA]*L

For B solution  

1.0 = e*[cB]*L

Hence

\frac{0.4}{ 1} = \frac{[cA]}{ cB}

[cB] = 2.5 [cA]

Therefore

Concentration of solution B is 2.5 times more than solution A's concentration.

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7 0
2 years ago
How many grams of CaCl 2 are in .48 moles ?
Llana [10]

Answer:

We assume you are converting between moles CaCl2 and gram. You can view more details on each measurement unit: molecular weight of CaCl2 or grams This compound is also known as Calcium Chloride. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles CaCl2, or 110.984 grams.

7 0
3 years ago
Read 2 more answers
A sample of water vapor has a volume of 3.15 L, a pressure of 2.40 atm, and a temperature of 325 K. What is the new temperature,
lara31 [8.8K]

Answer:

The answer to your question is:   T2 = 235.44 °K

Explanation:

Data

V1 = 3.15 L                    V2 = 2.78 L

P1 = 2.40 atm               P2 = 1.97 atm

T1 = 325°K                    T2 = ?

Formula

\frac{P1V1}{T1} = \frac{P2V2}{T2}

Process

            T2 = (P2V2T1) / (P1V1)

            T2 = (1.97x 2.78x 325) / (2.40 x 3.15)

            T2 = 1779.895 / 7.56

            T2 = 235.44 °K

4 0
3 years ago
PLEASE HELP ME BABES AND ASAP PLEASE!!
Goryan [66]
What special structures are needed for green plants?
<span> A.chloroplasts and chlorophyll

</span>
<span> What happens during the light reaction of photosynthesis? </span>
<span> D. Water molecules split apart. (Not 100%) </span>
5 0
3 years ago
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