All categories

3 years ago

7th Grade

Physics

1 answer:

slamgirl [31]3 years ago

3 0

A is the correct answer: 100 degrees C is the boiling point of water, just subtract 82 from 100.

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g A 475-gram ball is traveling horizontally at 12.0 m/s to the left when it is suddenly struck horizontally by a bat, causing it

AlexFokin [52]

Answer:

7.64 ms

Explanation:

3 0

3 years ago

A rock is dropped from a vertical cliff. The rock takes 6.00 s to reach the ground below the cliff. What is the height of the cl

Lana71 [14]

Answer:

180 m

Explanation:

The rock follows a free-fall motion - so the vertical distance covered can be found by using the equation

$h=\frac{1}{2}gt^2$

where

g = 10 m/s^2 is the acceleration due to gravity

t = 6.00 s is the time of the fall

Substituting these data, we find the height of the cliff:

$h=\frac{1}{2}(10 m/s^2)(6.00 s)^2=180 m$

4 0

4 years ago

Which of the following is a mixture?<br> a air<br> biron<br> Chydrogen<br> d nickel

Korolek [52]

The answer is Chydrogen

5 0

3 years ago

You’re squeezing a springy rubber ball in your hand. If you push inward on it with a force of 1 N, it dents inward 2 mm. How far

creativ13 [48]

Answer:

10mm

Explanation:

According to Hooke's law which states that "the extension of an elastic material is directly proportional to the applied force provided the elastic limit is not exceeded. Direct proportionality there means, increase/decrease in the force leads to increase/decrease in extension.

Mathematically, F = ke where;

F is the applied force

k is the elastic constant

e is the extension

from the formula k = F/e

k = F1/e1 = F2/e2

Given force of 1N indents the spring inwards by 2mm, this means force of 1N generates extension of 2mm

Let F1 = 1N e1 = 2mm

The extension that will be produced If force of 5N is applied to the string is what we are looking for. Therefore F2 = 5N; e2= ?

Substituting this values in the formula above we have

1/2=5/e2

Cross multiplying;

e2 = 10mm

This shows that we must have dent it by 10mm before it pushes outwards by a 5N force

8 0

4 years ago

At a particular instant the magnitude of the gravitational force exerted by a planet on one of its moons is 7 × 1021 N. Collapse

9966 [12]

Answer:

Fg = 4.2*10²² N

Explanation:

The gravitational force between any two masses, provided that can be approximated by point masses (comparing their diameters with the distance between them), obeys the Newton's Universal Law of Gravitation, which states that the force (always attractive) is proportional to the product of the masses and inversely proportional to the square of the distance between them (this as a consequence of our Universe being three-dimensional), as follows:

$Fg =\frac{G*m1*m2}{r^{2}}$

So, if one of the masses increases 6 times, the force between them will be directly 6 times larger, so the new magnitude of the force will be as follows:

Fg₂ = Fg₁*6 = 7*10²¹ N* 6 = 4.2*10²² N

7 0

3 years ago