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Delicious77 [7]
2 years ago
6

Which of the following statements is not true regarding acids?

Chemistry
2 answers:
Romashka [77]2 years ago
7 0
"Active metals will react with acids in double replacement reactions" is the statement among the following statements that <span>is not true regarding acids. The correct option among all the options that are given in the question is the last option or option "D". I hope that this answer has helped you.</span>
shepuryov [24]2 years ago
3 0
I believe the statement that is not true regarding acids is most likely D. Active metals will react with acids in double replacement reactions. It should be that reactive active metals will react with acids in single replacement reactions.
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maksim [4K]

Explanation:

According to the analysis, Molarity is amount mole per volume(1L). the amount in mole would be molarity × volume in litres.

0.500M × (250/1000)L= 0.125moles.

I hope this helps**

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3 years ago
2. What is the difference between an organ and an organ system
aleksandrvk [35]
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The formula weight of magnesium hydroxide is________ amu.<br> amu.
wlad13 [49]

Answer:

58.316  is the formula weight of magnesium hydroxide

5 0
2 years ago
covalent bond would be formed in which pair of elements? Carbon and oxygen, any two noble gasses, sodium and chlorine , between
SOVA2 [1]

Answer:

Carbon and Oxygen, Argon and Helium.

Explanation:

noble gases have full outer shells of electrons, and so cannot share other atoms' electrons to form bonds. sodium and chlorine form an ionic bond.

4 0
3 years ago
if the mass of 191 grams NaCl reacted with 74 frams of calcium hydroxide and 80 grams of sodium hydroxide is produced, what mass
nadya68 [22]
<h3>Answer:</h3>

110.98 g/mol

<h3>Explanation:</h3>

The reaction between NaCl and Ca(OH)₂ is given by the equation;

2NaCl(aq) + Ca(OH)₂(s) → 2NaOH(aq) + CaCl₂(aq)

We are required to determine the mass of CaCl₂ produced,

We will use the following simple steps;

Step 1: Moles of NaCl and Ca(OH)₂ given

Number of moles = Mass ÷ Molar mass

Moles of NaCl

Mass of NaCl = 191 g

Molar mass NaCl = 58.44 g/mol

Number of moles = 191 g ÷ 58.44 g/mol

                             = 3.268 moles

                             = 3.27 Moles

Moles of Ca(OH)₂

Mass of Ca(OH)₂ = 74 g

Molar mass of Ca(OH)₂ = 74.093 g/mol

Number of moles = 74 g ÷ 74.093 g/mol

                             = 0.998 mole

                              = 1.0 mole

However, from the equation  2 moles of NaCl requires 1 mole of Ca(OH)₂

Therefore, from the amount of reactants available NaCl was in excess and Ca(OH)₂ is the limiting reactant .

Step 2: Moles of CaCl₂ produced

From the equation

1 mole of Ca(OH)₂ reacts with NaCl to produce 1 mole of CaCl₂

Therefore; the mole ratio of Ca(OH)₂ to CaCl₂ is 1: 1

Thus;

Moles of CaCl₂ produced is 1.0 moles

Step 3: Mass of CaCl₂ produced

Moles of CaCl₂ = 1.0 mole

Molar mass CaCl₂ = 110.98 g/mol

But; mass = number of moles × Molar mass

Therefore;

Mass of CaCl₂ = 1.0 mole × 110.98 g/mol

                       = 110.98 g CaCl₂

3 0
2 years ago
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