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Margarita [4]
2 years ago
5

identify the correct practices when setting up the condenser for a reflux system. select one or more:

Chemistry
1 answer:
erastovalidia [21]2 years ago
6 0

The correct practices when setting up the condenser for a reflux system are option(c)and (d)i.e, to Grease the joint between the flask and the condenser and Align the flask so that the condenser is vertical.

A condenser's purpose is to transfer heat from a working fluid—in a steam power plant, for instance, water—to a secondary fluid or the ambient air. The effective heat transfer that takes place during phase shifts, in this case during the condensation of vapor into a liquid, is what powers the condenser.

A condenser is a heat exchanger used in heat transfer systems to cool a gaseous substance so that it condenses into a liquid condition. By doing this, the substance releases its latent heat and transfers it to the environment. On the back of a refrigerator, the condenser is located and is probably pretty dusty. The refrigerant cools down within and condenses, changing back from a gas to a liquid.

Learn more about condenser here:

https: //brainly.com/question/15563071

#SPJ4

The complete question is:

Identify the correct practices when setting up the condenser for a reflux system.

Select one or more:

-Clip the stopper in the top of the condenser.

-Start the heat before the condenser water to test the set-up.

-Grease the joint between the flask and the condenser.

-Align the flask so that the condenser is vertical.

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Answer:

Numbers of electrons transferred in the electrolytic or voltaic cell is 6 electrons.

Explanation:

Fe^{3+} (aq) + 3 e^-\rightarrow Fe (s) ,E^o = -0.036 V

Mg^{2+}(aq) + 2 e^- \rightarrow Mg (s),E^o = -2.37 V

The substance having highest positive reduction E^o potential will always get reduced and will undergo reduction reaction.

Reduction : cathode

Fe^{3+} (aq) + 3 e^-\rightarrow Fe (s) ,E^o = -0.036 V..[1]

Oxidation: anode

Mg(s)\rightarrow Mg^{2+}(aq) + 2 e^-,E^o = 2.37 V..[2]

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{red,cathode}-E^o_{red,anode}

E^o_{cell}=-0.036V-(-2.37 V)=2.334 V

The overall reaction will be:

2 × [1] + 3 × [2] :

2Fe^{3+} (aq) + 3Mg(s)+6e^-\rightarrow 2Fe (s)+3Mg^{2+}(aq)+6e^-

Electrons on both sides will get cancelled :

2Fe^{3+} (aq) + 3Mg(s)\rightarrow 2Fe (s)+3Mg^{2+}(aq)

Numbers of electrons transferred in the electrolytic or voltaic cell is 6 electrons.

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Silver and Gold belong to a special group of metals known as the native metals. They are found naturally on their own and not in combined form in rocks.

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