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Margarita [4]
2 years ago
5

identify the correct practices when setting up the condenser for a reflux system. select one or more:

Chemistry
1 answer:
erastovalidia [21]2 years ago
6 0

The correct practices when setting up the condenser for a reflux system are option(c)and (d)i.e, to Grease the joint between the flask and the condenser and Align the flask so that the condenser is vertical.

A condenser's purpose is to transfer heat from a working fluid—in a steam power plant, for instance, water—to a secondary fluid or the ambient air. The effective heat transfer that takes place during phase shifts, in this case during the condensation of vapor into a liquid, is what powers the condenser.

A condenser is a heat exchanger used in heat transfer systems to cool a gaseous substance so that it condenses into a liquid condition. By doing this, the substance releases its latent heat and transfers it to the environment. On the back of a refrigerator, the condenser is located and is probably pretty dusty. The refrigerant cools down within and condenses, changing back from a gas to a liquid.

Learn more about condenser here:

https: //brainly.com/question/15563071

#SPJ4

The complete question is:

Identify the correct practices when setting up the condenser for a reflux system.

Select one or more:

-Clip the stopper in the top of the condenser.

-Start the heat before the condenser water to test the set-up.

-Grease the joint between the flask and the condenser.

-Align the flask so that the condenser is vertical.

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Which of the following is a good conductor of electricity?
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Explanation:

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What is the charge of an atom's nucleus of an atom has 20 protons, 23 neutrons, and 18 electrons?
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It would have a charge of +2.

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An interpenetrating primitive cubic structure like that of CsCl with anions in the corners has an edge length of 664 pm. If the
san4es73 [151]

Answer:

the ionic radius of the anion r^- = 312.52 \ pm

Explanation:

From the diagram shown below :

The anion Cl^- is located at the corners

The cation Cs^+ is located at the body center

The Body diagonal length =  \sqrt{3 \ a }

∴ 2 \ r^+ \ + 2r^- \ = \sqrt{3 \ a}  \\ \\ r^+ +r^- = \frac{\sqrt{3}}{2} a

Given that :

\frac{r^+}{r^-} =0.84   (i.e the  ratio of the ionic radius of the cation to the ionic radius of

                 the anion )

0.84r^- \ + r^- \ = \frac{\sqrt{3}}{2}a  \\ \\  1.84 r^- = \frac{3}{2}a \\ \\ r^- = \frac{\sqrt{3}}{2*1.84}a

Also ; a =  664 pm

Then :

r^- = \frac{\sqrt{3} }{2*1.84}*664 \ pm\\ \\ r^- = 312.52 \ pm

Therefore,  the ionic radius of the anion r^- = 312.52 \ pm

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3 years ago
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