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Anuta_ua [19.1K]
3 years ago
11

What quantity is measured in mol/dm³?

Chemistry
1 answer:
natima [27]3 years ago
3 0
L
M =  \frac{n}{V}  \\ M = \frac{mol}{L}  \\ or \\ M =  \frac{mol}{ {dm}^{3} }
mol/dm³ is measure for molarity
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What is the hybridization of the nitrogen atom in ammonia?
dybincka [34]

The nitrogen atom in NH3 is sp3 hybridized. ... In NH3 molecule, three of the sp3 orbitals are used to formbonds to the three hydrogen atoms and the fourth sp3 orbital is used to hold the lone pair. and is sometimes called a non-bonding pair.

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In the Reaction CuCl2 + 2 NaNO3 —> Cu(NO3)2 + 2 Naci
Lunna [17]

Explanation:

The molar mass of the compounds are incorrect

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Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a tank
Masja [62]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The concentration equilibrium constant is K_c  = 14.39

Explanation:

The chemical equation for this decomposition of ammonia is

                2 NH_3  ↔   N_2 + 3 H_2

The initial concentration of ammonia is mathematically represented a

          [NH_3] =  \frac{n_1}{V_1}  = \frac{29}{75}

          [NH_3] = 0.387  \  M

The initial concentration of nitrogen gas  is mathematically represented a

         [N_2] =  \frac{n_2}{V_2}

         [N_2] =  0.173  \  M

So  looking at the equation

   Initially (Before reaction)

      NH_3 = 0.387 \ M

      N_2  =  0 \  M

      H_2 =  0 \ M

During reaction(this is gotten from the reaction equation )

        NH_3 = -2 x(this implies that it losses two moles of concentration )

         N_2 = + x  (this implies that it gains 1 moles)

         H_2  =  +3 x(this implies that it gains 3 moles)

Note : x denotes concentration

At equilibrium

        NH_3 = 0.387 -2x

       N_2 =  x

        H_2  =  3 x

Now since

     [NH_3] = 0.387  \  M

     x= 0.387  \  M    

H_2  =  3 * 0.173    

H_2  =  0.519 \ M    

NH_3 = 0.387 -2(0.173)

NH_3 = 0.041 \ M

Now the equilibrium constant is

           K_c  =  \frac{[N_2][H_2]^3}{[NH_3]^2}

substituting values

           K_c  =  \frac{(0.173) (0.519)^3}{(0.041)^2}

           K_c  = 14.39

         

3 0
3 years ago
Which would have more mass: a mole of sodium or a mole of copper? How do you know?
bearhunter [10]

Answer:

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Explanation:

so for this you can work out the mass for both and compare

so mass = moles × mr

so mass of sodium = 1 × 23= 23 g

and mass of copper = 1 × 63.5= 63.5 g

so copper have more mass :)

5 0
3 years ago
True or false if an object displaces 50 ml of water the object's volume is 50mL
andrew11 [14]

Answer:

True

Explanation:

The volume of water displaced by an object completely submerged is its actual volume. It implies that in the container the object create a space of size for itself which is the volume of the object. This approach is used in calculating the density of many irregular solids from their measured masses.

6 0
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