What is the solubility of methylacetylene (in units of grams per liter) in water at 25 °C, when the C3H4 gas over the solution h
1 answer:
Answer:
The solubility of methylacetylene is 0,11 g L⁻¹
Explanation:
Henry's law is a gas law that states that the amount of dissolved gas in a liquid is proportional to its partial pressure above the liquid.
The formula is:
C = kH P
Where C is solubility of the gas (In mol/L)
kH is Henry constant (9,23x10⁻² mol L⁻¹ atm⁻¹)
An P is partial pressure (0,301 atm)
Solving, C = 2,78x10⁻³ mol L⁻¹. In grams per liter:
2,78x10⁻³ mol L⁻¹ₓ = <em>0,11 g L⁻¹</em>
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The fraction of gas phase molecules is calculated by the division of final pressure to the initial pressure.
Fraction = (1)
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final pressure =
First, convert torr into atm
1 atm = 760 torr
final pressure =
=
Now, put the value of initial and final pressure in formula (1)
Fraction =
=
Thus, fraction of the gas phase molecules =